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swat32
2 years ago
11

A softball team played 149 games. The team won 8 more than two times the number of games they lost. How many games did they lose

?
Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
6 0

The number of game the softball team lose is 47 games.

<h3 /><h3 /><h3>The softball team played 149 games. </h3>

Total games played = 149 games

The team won 8 more than two times the number of games they lost.

Let

the number of games they lost = x

Therefore,

  • number of game won = 8 + 2x

The number of game they lose can be calculated as follows:

8 + 2x + x = 149

8 + 3x = 149

3x = 149 - 8

3x = 141

x = 141 / 3

x = 47

Therefore, the team lost 47 games.

learn more on algebra here: brainly.com/question/14406047?referrer=searchResults

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Rudy has 10 white she sells 23 pink seashells and 21 Brown see cells if he divides the cells into equally between three friends
Alex_Xolod [135]

Answer:

Each friend will get 18 sea shells.

Step-by-step explanation:

Given:

Rudy has white sea shells = 10

Rudy has pink sea shells = 23

Rudy has brown sea shells = 21

Number of friends = 3

Rudy divides the sea shells into equally between three friends.

We need to find how many sea shells each friend can get.

Now first we find the total number sea shells.

Total number of sea shells = white sea shells + pink sea shells + brown sea shells = 10 + 23 + 21 = 54

Now to find number of sea shell each friend can get we will divide total number of sea shell with number of friends.

number of sea shell each friend can get = \frac{\textrm{Total number of sea shells}}{\textrm{ Number of friends}} = \frac{54}{3}=18

Hence each friend will get 18 sea shells.

8 0
3 years ago
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Blizzard [7]
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Solve : n-6 = 0

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3 0
3 years ago
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Step-by-step explanation:

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Aloiza [94]
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