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Doss [256]
3 years ago
6

If a Ball Falls from a girls hand, How does its speed change?

Physics
2 answers:
Lapatulllka [165]3 years ago
7 0

Answer:

When an object is in free fall, gravity increases its velocity by 9.8 m/s with every passing second.

Explanation:

Hope Helps :)

Keith_Richards [23]3 years ago
3 0

Answer:

Yes

Explanation:

At initial condition the ball is in rest because girl hold the ball.But after when girl release the ball the due to gravity it speed goes to increase and become zero again when it touch the floor.

As we know that gravity  provides acceleration due to which velocity of ball increases.

Lets take the height of ball from the bottom was h ,so the velocity of ball just before when ball touch the bottom surface after falling from the hand of girl is V.

V=\sqrt{2gh}

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When is thermal equilibrium achieved between two objects?
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The half-life of Co-55 is 175 hours. How much of a 4000 g of Cobalt-55 sample would be left after 525 hours?
Harrizon [31]

We know that whatever amount we start with, half of it decays and forms atoms of other elements in 175 hours.  So in order to figure out how much is left after 525 hours, we'll need to know how many half-lifes pass in that amount of time.

Well, (525 divided by 175) is exactly 3 half-lifes.  So this will be easy.

-- After 1 half-life . . .

. . . . . 50% decays, 50% is still there.

-- After the 2nd half-life . . .

. . . . . (half of the leftover 50%) = another 25% decays, 25% is left.

-- After the 3rd half-life . . .

. . . . . (half of the leftover 25%) = another 12.5% decays, 12.5% is left.

12.5% of 4,000g = (0.125 x 4,000g) = <em>500 g</em> .

============================================

<u>Another way</u>:

After 1 half-life, 1/2 is left.

After 2 half-lifes, 1/4 is left.

After 3 half-lifes, 1/8 is left.

1/8 of 4,000g = (4,000g/8) = <em>500 g </em>.

5 0
3 years ago
When energy is transformed or changed from one form into another, some of the energy will be lost to the environment as?
sasho [114]
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3 years ago
The radius of curvature of both sides of a converging lens is 18 cm. One side of the lens is coated withsilver so that the inner
Dahasolnce [82]

Answer:

n = 1.4

Explanation:

Given,

R1 = 18 cm, R2 = -18 cm

From lens makers formula

1/f = (n - 1)(1/18 + 1/18) = (n-1)/9

f = 9/(n-1)

Power, P = 1/f ( in m) = (n-1)/0.09

Now, this lens is in with conjunction with a concave mirror which then can be thought of as to be in conjunction with another thin lens

Power of concave mirror = P' = 1/f ( in m) = 2/R = 2/0.18 = 1/0.09

Net power of the combination = 2P + P' = 2(n-1)/0.09 + 1/0.09 = 1/0.05

n = 1.4

7 0
2 years ago
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