Answer:
0.35
Explanation:
According to Newton's second law;
\sum Fx = ma
Fm - Ff =ma
Fm is the moving force = Wsin theta
Fm = 4(9.8)sin55
Fm = 32.1N
Ff is the frictional force = nmgcos theta
Ff = n(4)(9.8)cos55
Ff = 22.48n
Acceleration a = 6.0m/s²
Substitute the given values into the formula and get the coefficient of friction
32.11-23.48n = 4(6)
32.11-24= 23.48n
8.11 = 23.48
n = 8.11/23.48
n = 0.35
Hence the coefficient of friction is 0.35
The elements which have similar behavior are Barium, strontium and beryllium.
Answer:
437 J
Explanation:
Parameters given:
Weight of child, W = 230 N
Height of swing, h = 1.9 m
Gravitational Potential Energy is given as:
P. E. = m*g*h = W*h
m = mass
h = height above the ground
W = weight
P. E. = 230 * 1.9
P. E. = 437 J
The unit of force is the 'Newton'.
1 newton is the force that accelerates 1 kilogram of mass
at the rate of 1 meter per second-squared.
1 N = 1 kg-m/s²
-- A force of 1 pound is about 4.448 newtons.
-- A force of 1 newton is about 3.6 ounces.
Answer:
Explanation:
For an electric force, F the formula:
F = kQq/r^2
Given:
r2 = 1/2 × r1
F1 × r1 = k
F1 × r1 = F2 × r2
F2 = (F1 × r1^2)/(0.5 × r1)^2
= (F1 × r1^2)/0.25r1^2
= 4 × F1.
