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3 years ago

If a Ball Falls from a girls hand, How does its speed change?

Physics

2 answers:

Lapatulllka [165]3 years ago

7 0

Answer:

When an object is in free fall, gravity increases its velocity by 9.8 m/s with every passing second.

Explanation:

Hope Helps :)

Keith_Richards [23]3 years ago

3 0

Answer:

Yes

Explanation:

At initial condition the ball is in rest because girl hold the ball.But after when girl release the ball the due to gravity it speed goes to increase and become zero again when it touch the floor.

As we know that gravity provides acceleration due to which velocity of ball increases.

Lets take the height of ball from the bottom was h ,so the velocity of ball just before when ball touch the bottom surface after falling from the hand of girl is V.

$V=\sqrt{2gh}$

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which actions most likely cause the domains within a material to lose their alignment and become more randomized

zimovet [89]

answer:

heating the material

placing the material in a magnetic field of opposite polarity

hitting the material

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3 years ago

Read 2 more answers

The acceleration due to gravity on the moon is about 1/6 of the acceleration due to gravity on the earth. A net force F acts hor

uysha [10]

Answer:

c. $a_m$

Explanation:

We are given that

Acceleration due to gravity on the moon= $a_m$

Acceleration due to gravity on the earth= $a_e$

$g_m=\frac{1}{6}g_e$

Net force due to am on an object on moon= $F_{net}=ma_m$

There is no friction and no drag force and there is no gravity involved

Then, the force acting on an object on earth= $F=ma_e$

$F=F_{net}$ (given)

$ma_m=ma_e$

$a_e=a_m$

Hence, option c is true.

3 0

3 years ago

What are the answers please help

aleksandr82 [10.1K]

Answer:

a.) The main scale reading is 10.2cm

b.) Division 7 = 0.07

c.) 10.27 cm

d.) 10.31 cm

e.) 10.24 cm

Explanation:

The figure depicts a vernier caliper readings

a.) The main scale reading is 10.2 cm

The reading before the vernier scale

b.) Division 7 = 0.07

the point where the main scale and vernier scale meet

c.) The observed readings is

10.2 + 0.07 = 10.27 cm

d.) If the instrument has a positive zero error of 4 division

correct reading = 10.27 + 0.04 = 10.31cm

e.) If the instrument has a negative zero error of 3 division

correct reading = 10.27 - 0.03 = 10.24cm

3 0

4 years ago

An electron with a speed of 0.95c is emitted by a supernova, where cc is the speed of light. What is the magnitude of the moment

krok68 [10]

Answer:

2.59×10¯²² Kgm/s

Explanation:

Data obtained from the question include:

Velocity of electron = 0.95c

Momentum =?

Next, we shall determine the velocity of the electron. This can be obtained as follow:

Velocity of electron = 0.95c

Velocity of Light (c) = 3×10⁸ m/s

Velocity of electron = 0.95c

Velocity of electron = 0.95 × 3×10⁸

Velocity of electron = 2.85×10⁸ m/s

Finally, we shall determine the mometum of the electron.

Momentum is simply defined as the product of mass and velocity. Mathematically, it is expressed as:

Momentum = mass x Velocity

Thus, with the above formula, we calculate the momentum of the electron as follow:

Mass of electron = 9.1×10¯³¹ Kg

Velocity of electron = 2.85×10⁸ m/s

Momentum of electron =?

Momentum = mass x Velocity

Momentum = 9.1×10¯³¹ × 2.85×10⁸

Momentum = 2.59×10¯²² Kgm/s

Therefore, the momentum of the electron is 2.59×10¯²² Kgm/s

3 0

3 years ago

An airplane during departure has a constant acceleration of 3 m / s².

Rama09 [41]

Constant acceleration of plane = 3m/s²

a) Speed of the plane after 4s

Acceleration = speed/time

3m/s² = speed/4s

S = 12m/s

The speed of the plane after 4s is 12m/s.

b) Flight point will be termed as the point the plane got initial speed, u, 20m/s

Find speed after 8s, v

a = 3m/s²

from,

a = v - u

3 = v - 20

24 = v - 20

v = 44m/s

After 8s the plane would've 44m/s speed.

6 0

3 years ago