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Doss [256]
2 years ago
6

If a Ball Falls from a girls hand, How does its speed change?

Physics
2 answers:
Lapatulllka [165]2 years ago
7 0

Answer:

When an object is in free fall, gravity increases its velocity by 9.8 m/s with every passing second.

Explanation:

Hope Helps :)

Keith_Richards [23]2 years ago
3 0

Answer:

Yes

Explanation:

At initial condition the ball is in rest because girl hold the ball.But after when girl release the ball the due to gravity it speed goes to increase and become zero again when it touch the floor.

As we know that gravity  provides acceleration due to which velocity of ball increases.

Lets take the height of ball from the bottom was h ,so the velocity of ball just before when ball touch the bottom surface after falling from the hand of girl is V.

V=\sqrt{2gh}

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Which properties of a lava lamp are important to remember when modeling convection?
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3 years ago
18. How does magnetic force affect the energy in a system of magnets when the magnets are released and begin to move? a The magn
astra-53 [7]

When the magnets are released and begin to move, the magnetic force changes potential energy into kinetic energy;<u> option D</u>

<h3>What is magnetic force?</h3>

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Magnetic force is the force that exists due to the attractio or repulsion of objects place around the region of space where a maget exerts its force.

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5 0
1 year ago
An electron in a cathode-ray beam passes between 2.5cm long parallel-plate electrodes that are 6.0mm apart. A 2.1mT, 2.5-cm-wide
Dmitry_Shevchenko [17]

Answer:

(a). The speed of electron is 1.56\times10^{7}\ m/s.

(b). The radius of electron is 4.2\ cm

Explanation:

Given that,

Length = 2.5 cm

Distance = 6.0 mm

Magnetic field = 2.1 T

Potential difference = 700 V

(a). We need to calculate the electron's speed

Using formula of speed

v=\sqrt{\dfrac{2eV}{m}}

Put the value into the formula

v=\sqrt{\dfrac{2\times1.6\times10^{-19}\times700}{9.1\times10^{-31}}}

v=15689290.81\ m/s

v=1.56\times10^{7}\ m/s

(b). We need to calculate the radius of electron

Using formula of centripetal force

\dfrac{mv^2}{r}=qvB

r=\dfrac{mv}{qB}

Where,

m = mass of electron

v = speed of electron

r = radius

q = charge of electron

B = magnetic field

Put the value into the formula

r=\dfrac{9.1\times10^{-31}\times1.56\times10^{7}}{1.6\times10^{-19}\times2.1\times10^{-3}}

r=0.042\ m

r=4.2\ cm

Hence, (a). The speed of electron is 1.56\times10^{7}\ m/s.

(b). The radius of electron is 4.2 cm

8 0
3 years ago
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