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amm1812
4 years ago
14

The force exerted by expanding gases is what propels a shell out of a gun barrel. Suppose a force that has an average magnitude

F propels the shell so that it has a speed v at the instant it reaches the end of the barrel.
A) What magnitude force is required to double the speed of the shell in the same gun?
Physics
1 answer:
masya89 [10]4 years ago
8 0

Answer: 2F

Explanation:

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According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.

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F=k_e\frac{q_1q_2}{r^2}

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First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'

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Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.

F_{sp}=k_e\frac{qq}{2^2}=k_e\frac{q^2}{4}     ...........(2)

Equation equation 1 and 2, we get

\frac{F_{sq}}{F_{sp}}=\frac{1}{4}

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