Answer:
1.54 m/s²
Explanation:
The free-fall acceleration is calculated as
g = w²r
Where w is the angular velocity of the satellite and r is the radius of the moon.
The angular velocity can be calculated as
Where T is the period, so
T = 110 min = 110 x 60 s = 6600 s
Then,
Finally, the radius of the moon is r = 1.7 x 10⁶ m, so the free-fall acceleration is
Therefore, the answer is 1.54 m/s²
Answer:
0 m/s
Explanation:
The cannonball was launched horizontally, which means that it had no vertical distance and utterly no vertical speed. If you separate diagonal speed into components, the vertical component would be 0.
The cannonball would go in a sad little arc from 90 degrees, accelerating lower and lower due to gravity.
(1 parsec) is the distance at which an object has a parallax of 1 arcsecond. The distance is about 3.26 light years.
Another way to understand it is: The distance from which the Earth's orbit appears 1 arcsecond across.
For a parallax angle of 1/2 arcsecond, the distance is <em>2 parsecs </em>(about 6.52 light years).
1 arcsecond is 1/3600 of a degree, 0.00028 degree.