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Studentka2010 [4]
3 years ago
10

Which quadrant of the coordinate plane would you use to graph time and distance?

Mathematics
2 answers:
Tema [17]3 years ago
6 0
The second quadrant
jeka943 years ago
5 0
That is correct u should give him brainless
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7x-4y=20 for y when x=3
viktelen [127]
I think it is y=-.25
7*3 - 4y = 20
21 - 4y = 20
subtract 21 from each side
- 4y = - 1
divide each side by - 4
y= -.25
6 0
3 years ago
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What is 18 times 40 to the 9th power
Rzqust [24]
I believe thugs is it
4.718592e+15
3 0
3 years ago
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If f(x)=2x+1 and g(x)=1/2(x-1), what does f(g(-4)) equal
uranmaximum [27]
G(-4)

=1/2((-4)-1)

=1/2(-5)

=-2.5

------------------------------

f(g(-4))

=f(-2.5)

=2(-2.5)+1

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5 0
3 years ago
In a polynomials equation do you add the exponents if they are different
Alexus [3.1K]
You can only add exponents if you are multiplying two of the same variable together. For example,
x^{12} \times x^4 = x^{16}

You take them away if you are dividing.
<span>x^{12} \div x^4 = x^{8}

In a polynomial equation, you can add together two of the same variable if they have the same exponent
</span>3x^4 + 7x^4 = 10x^4

Or you can take them away in a similar fashion,
<span>3x^4 - 7x^4 = -4x^4

But you cannot add two (or more) different exponents,
</span>6+4x+7x^2 = 6+4x+7x^2 (it does not get any simpler)

I hope this has answered your question, if not, leave a comment and I'll update the answer.
4 0
3 years ago
At the U.S open tennis championship a statistician keeps track of every serve that a player hits during the tournament. The mean
GarryVolchara [31]

Answer:

Step-by-step explanation:

Both 115 and 145 mph are above the mean.  Draw a normal curve and mark these speeds.  115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.

We need to find the area under the standard normal curve between 115 and 145.  This is equivalent to the area under the standard normal curve between z = 1 and z = 3.

I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area:  normalcdf(1, 3) = 0.1573.

The area between z = 1 and z = 3 is 0.1573.  In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.

8 0
2 years ago
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