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Studentka2010 [4]
3 years ago
10

Which quadrant of the coordinate plane would you use to graph time and distance?

Mathematics
2 answers:
Tema [17]3 years ago
6 0
The second quadrant
jeka943 years ago
5 0
That is correct u should give him brainless
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My first expression answer is y=5 -2x How do I plug it into x-y=1 ?? The Y
Lemur [1.5K]

Answer:

All you need to do is make sure the first expression is solved for y (which it is), and then substitute it into the second expression in place of any occurrences of y:

given the second expression:

x - y = 1

We'll replace y with it's value in the first expression:

x - (y) = 1

x - (5 - 2x) = 1

Now we can expand the resulting equation:

x - 5 + 2x = 1

So <em>neither</em> of the answers provided are correct.

You can then solve for x:

x - 5 + 2x = 1

x - 5 + 5 + 2x = 1 + 5

x + 2x = 6

3x = 6

3x/3 = 6/3

x = 2

After that, you can find y by plugging x into either of the two original equations:

y = 5 - 2x

y = 5 - 2(2)

y = 5 - 4

y = 1

8 0
3 years ago
What is the solution to the inequality below?
anastassius [24]
B because a negative squared is always a positive and it has to be a negativ number less than -3 is less than 9 and if it is greater than 3 than it would make it untrue.

3 0
3 years ago
Read 2 more answers
Earth orbits the sun in an elliptical pattern. The equation of Earth's path is.... where the measurements represent millions of
Triss [41]

General equation of Ellipse centered at (h,k) is given as

\frac{(x-h)^{2}}{a^{2}} + \frac{(y-k)^{2}}{b^{2}} =1\\

where a is the radius along x-axis

and b is radius along y-axis.

Given : The equation of elliptical path of Earth as

\frac{(x+2.5)^{2}}{22350.25} + \frac{y^{2}}{22344} = 1\\

Comparing the equation with the general equation, we get

(h,k) as (-2.5,0)

a = \sqrt{22350.25} = 149.5

b = \sqrt{22344} = 149.48

We have the Sun located at the coordinate (0,0).

Hence, the distance between Sun and Earth in July = 149.5 + 2.5 =152

∴ Earth's distance from the Sun in July is 152 million kilometers.



5 0
3 years ago
HELP please!
mars1129 [50]
The answer would be B, (6,-3) because when you plug in the x and y values into the inequality, it is the only result that is true
8 0
3 years ago
If a triangle has side lengths 7, 10, and 12, is it a right triangle??
Vesnalui [34]

Answer:

No. Remember, a right angle must have a 90 degree angle. We can find the lengths with the Pythagorean Theorem.

Step-by-step explanation:

Given the length 7, 10, and 12, we can assume that 12 is the hypotenuse (it is the longest length).

- we can use 7 and 10 interchangeably.

Fill in the equation, a^2 + b^2 = c^2

                 where c = 12, and a or b = 7 or 10.

To indicate if the given lengths would form a right angle, we can only input 7 or 10, not both.

Therefore, 7^2 + b^2 = 12^2 or 10^2 + b^2 = 12^2

7^2 + b^2 = 12^2 ==> 49 + b^2 = 144 ==> <u>b= </u>\sqrt{95<u> ==> </u><u>9.746</u>

b= 9.7, not 10.

10^2 + b^2 = 12^2 ==> 100 + b^2 = 144 ==> <u>b = </u>\sqrt{44<u> ==> </u><u>6.633 </u>

b= 6.6, not 7.

Therefore, the lengths 7, 10, and 12, does NOT make a right triangle.

Hope this helps!

5 0
3 years ago
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