All categories

3 years ago

Which equation, in point-slope form, passes through (-2, 4) and has a slope of 3?

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

7 0

Answer:

B. Y-4 =3(x+2)

You might be interested in

Multiple choice question?

nydimaria [60]

Answer:

9* 3 ^ (x-2)

Step-by-step explanation:

g(x) = 3^x

We know a^ (b) * a^(c) = a^ (b+c)

9* 3 ^ (x+2) = 3^2 * 3 ^(x+2) = 3^(2+x+2) = 3^x+4 not equal to 3^x

3*(9^(x+2)) = 3*3^2(x+2) = 3^1 * 3^(2x+4) =3^(2x+4+1) = 3^(2x+5) not equal

9* 3 ^ (x-2) = 3^2 * 3 ^(x-2) = 3^(2+x-2) = 3^x equal to 3^x

3*(9^(x-2)) = 3*3^2(x-2) = 3^1 * 3^(2x-4) =3^(2x-4+1) = 3^(2x-3) not equal

6 0

4 years ago

Read 2 more answers

Sally is planning a trip for 225 students.

sdas [7]

Answer:

Number of students want to go to Theme Park = 75

Step-by-step explanation:

Note: The given question is incomplete. Complete question is as follow.

Given:

Number of sample student = 30

Place Number of students want to go

Theme Park 10

Theater 5

Sports Center 8

Seaside 7

Find:

How many students want to go to Theme Park.

Computation:

⇒ Probability for students want to go to Theme Park = 10 / 30

⇒ Probability for students want to go to Theme Park = 1 / 3

⇒ Number of students want to go to Theme Park = [1 / 3]225

⇒ Number of students want to go to Theme Park = 75

3 0

3 years ago

What triangle congruence postulate would prove that the two triangles are congruent?

Cerrena [4.2K]

Answer:

1.) SSS

Step-by-step explanation:

7 0

3 years ago

The ratio of time student spends on their art project to time the student spends on their science project is 3 to 4 the total am

tatiyna

To solve, start with this equation
$56 \div 7 = 8$
So, 8 times 3 gives you how long they spent on art and 8 times 4 gives you how long they spent on science. So they spent...
$8 \times 3 = 24 \: minutes \: on \: art$
and...
$8 \times 4 = 32 \: minutes \: on \: science$

3 0

3 years ago

Pre-Cal - Someone please help! (Image Attached)

olasank [31]

Note that $\displaystyle{ \sin30^{\circ}= \frac{1}{2}$ and $\displaystyle{ \cos30^{\circ}= \frac{ \sqrt{3}}{2}$ .

From the unit circle, we can check that $\sin30^{\circ}$ and $\sin(-30)^{\circ}$ have the same value, but opposite signs, that is:

$\sin(-30)^{\circ}=-\sin(30)^{\circ}=-\frac{1}{2}$ .

Thus,
$\displaystyle{ \cos(x-y)= \cos(-30^{\circ}-60^{\circ})=cos(-90^{\circ})$ .

Note that $cos(-90^{\circ})$ is the x-coordinate of the lowest point on the unit circle, that is (0, -1). Thus $cos(-90^{\circ})=0$

Answer: 0

6 0

4 years ago