All categories

3 years ago

Find the degree, leading coefficient, and the constant term of the polynomial.

Mathematics

1 answer:

Vikki [24]3 years ago

6 0

$\LARGE{ \boxed{ \purple{ \rm{Answers;)}}}}$

☃️ Degree of the polynomial- The highest degree of any term in a polynomial. Here the highest degree is 5.

⇛ 4x⁴ + 5 + 6x⁵ - 2x(° of polynomial = 5)

☃️ Leading coefficient- The coefficient of the term having the highest degree of the polynomial. Here, the highest degree is 5 and the term is 6x⁵

⇛ 4x⁴ + 5 + 6x⁵ - 2x (Leading coeff. = 6)

☃️ Constant term- It is the term having no coefficients, only a fixed real number. This remains constant in any value of polynomial.

⇛ 4x⁴ + 5 + 6x⁵ - 2x (Constant term = 5)

━━━━━━━━━━━━━━━━━━━━

You might be interested in

83 = y - 17 what the value of y

Artemon [7]

The answer is y = 100

To get this answer, you add 17 to both sides to undo the "minus 17" that is happening on the right side.

83 = y-17

83+17 = y-17+17 ... add 17 to both sides

100 = y

y = 100

3 0

3 years ago

Read 2 more answers

Which is equivalent to V180x11 after it has been simplified completely?

inna [77]

Question:

Which is equivalent to $\sqrt{180x^{11}}$ after it has been simplified completely?

Answer:

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

Step-by-step explanation:

Given

$\sqrt{180x^{11}}$

Required

Simplify

We start by splitting the square root

$\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}$

Replace 180 with 36 * 5

$\sqrt{180x^{11}} = \sqrt{36 * 5} * \sqrt{x^{11}}$

Further split the square roots

$\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} * \sqrt{x^{11}}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{11}}$

Replace power of x; 11 with 10 + 1

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10 + 1}}$

From laws of indices; $a^{m+n} = a^m * a^n$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x^1}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x}$

Further split the square roots

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10}} * \sqrt{x}$

From laws of indices; $\sqrt{a} = a^{\frac{1}{2}}$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{10*\frac{1}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{\frac{10}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{5} * \sqrt{x}$

Rearrange Expression

$\sqrt{180x^{11}} = 6 * x^{5} * \sqrt{5} * \sqrt{x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}$

From laws of indices; $\sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}$

So, we have

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}$

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

The expression can no longer be simplified

Hence, $\sqrt{180x^{11}}$ is equivalent to $6x^{5}\sqrt{5x}$

7 0

2 years ago

Read 2 more answers

In standard form: (x+5)(3x-1)-(x-4)^2

denpristay [2]

I hope this helps you

x.3x+x.(-1)+5.3x+5.(-1)-(x^2-2.4.x+16)

3x^2-x+15x-5-x^2+8x-16

2x^2+22x-21

6 0

3 years ago

Read 2 more answers

Can someone please answer this question please answer it correctly and please show work please help me I need it

WINSTONCH [101]

Answer:

Step-by-step explanation:

-19-11 = -19 + (-11)

3 0

3 years ago

Read 2 more answers

Simplify the expression (-1)^3* (-1)^2

Sergio [31]

Answer:1/6

Step-by-step explanation:

7 0

2 years ago