Question

Let p(a) = 0.49, p(b) = 0.24, and p(a |

Answer 1

$\mathbb P(A\cap B)=\mathbb P(A\mid B)\mathbb P(B)=0.106$

$\mathbb P(A\cup B)=\mathbb P(A)+\mathbb P(B)-\mathbb P(A\cap B)=0.624$

$\mathbb P(B\mid A)=\dfrac{\mathbb P(B\cap A)}{\mathbb P(A)}=0.216$