For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>
Answer:
Step-by-step explanation:
Let the rent be x
<u>Discounted rent </u>
<u>Increase applied</u>
<u>Final rent:</u>
- (x - 50) + 10% = (x - 50)*1.1
<u>We know this is equal to x + 5% = 1.05x, comparing now</u>
- 1.1(x - 50) = 1.05x
- 1.1x - 1.05x = 55
- 0.05x = 55
- x = 55/0.05
- x = $1100
Answer:
Answer b)
Step-by-step explanation:
In the sequence 0, 5, 10, 15,...
5 is added to each term in order to get the next one. Therefore the next three terms would be; 20, 25, 30.
This agrees with answer b) in the list of possible answers.
AE x BE = DE x CE
6x5 = 30
6 x DE = 30
DE = 30/6 =5
DC = DE +CE = 5+6 =11
Answer is C) 11
