All categories

2 years ago

Simplify 13 +4(9-7) and solve

Mathematics

2 answers:

nika2105 [10]2 years ago

8 0

Answer:

21 hope this helps

Step-by-step explanation:

Sliva [168]2 years ago

4 0

Answer:

Step-by-step explanation:

13 + 4(9-7) =

13 + 4(2) =

13 + 8 = 21

You might be interested in

Which equation is correctly rewritten to solve for x?

ikadub [295]

Answer:

Option (A)

Step-by-step explanation:

Te given equation is,

-qx + p = r

Toe find the value of x,

By subtracting p from both the sides of the equation.

-qx + p - q = r - q

-qx = r - q

By dividing the whole equation by (-q),

$\frac{-qx}{(-q)}=\frac{r-p}{-q}$

x = $-\frac{r-p}{q}$

x = $\frac{p-r}{q}$

Therefore, Option (A) will be the answer.

4 0

2 years ago

13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult

Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that $\frac{ab}{m}$ is and integer.

As m= vb, then $\frac{m}{b}$ is an integer, lets say $\frac{m}{b}$ =v; and as m=ua, then $\frac{m}{a}$ =u.

So $\frac{ab}{m}$ v= $\frac{ab}{m}$ $\frac{m}{b}$ =a, so $\frac{ab}{m}$ divides a; on the other hand, $\frac{ab}{m}$ u= $\frac{ab}{m}$ $\frac{m}{a}$ =b, so $\frac{ab}{m}$ divides b. From this we can conclude that $\frac{ab}{m}$ is a common divisor of a and b.