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faltersainse [42]

3 years ago

13

If the designers of submarines do not appropriately account for hydrostatic pressure,

1 answer:

andre [41]3 years ago

7 0

Answer:

A) the pressure could crush the submarine

Explanation:

The submarines are mainly used for defense purposes.
In world war 1 and 2 the submarines played a vital role in the war.
The submarines work according to the principle of buoyancy.
According to this principle, when seawater is filled inside the tank in a required amount, the submarines sink.
When the seawater is expelled, the submarine rises to above the sea.
Most of the time, it dives deep into the sea, the hydrostatic pressure should be taken into account.
If the hydrostatic pressure is not considered, the pressure could crush the submarine.

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joja [24]

ANSWER:100dB

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<em /> $\beta$ <em>₁=</em> $\beta$ <em>=(10dB)㏒₁₀(l₁/l₀)</em>

<em>inserting numbers:</em>

<em>120dB=(10dB)㏒₁₀[l₁/10⁻¹²W/m⁸] or 12=㏒₁₀[l₁/(10⁻¹²)W/m²</em>

<em>Getting the antilog of both sides and obtain 10¹²=l₁(10⁻¹²W/m²)which </em>

<em>can be used to solve for l₁ and get</em>

<em> l₁=(10⁻¹²W/m²)(10¹²)=1 W/m²</em>

<em>since the sound intensity is related to the power and that the power does not change,the sound intensity at any other point can be solved.Plugging-in</em>

<em>ᵃ = 4πr²,into P=l₁ₐ₁=l₂ₐ₂ and get:</em>

<em>l₂=l₁(r₁/r₂)² =(1W/m²)(5/35) =2.04×10⁻²W/m²</em>

<em>since we know the sound intensity at the sound point 2r,the sound intensity level at the point can be solved.We have:</em>

<em> </em> $\beta$ <em>₂=</em> $\beta$ <em>=(10dB)㏒₁₀(l₂/l₀)=(10dB)㏒₁₀(2.04×10⁻²/1×10⁻²)</em>

<em> </em> $\beta$ <em>₂=(10dB)㏒₁₀(2.04×10¹⁰)</em>

<em /> $\beta$ <em> =(10dB)[㏒₁₀(2.04)+㏒₁₀(10¹⁰)]=10dB[0.32+10]=103dB=100dB</em>

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MaRussiya [10]

Answer:

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Explanation:

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