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Butoxors [25]
3 years ago
14

A human services professional has worked with a particular client for a couple of years. The client

Physics
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

Respect the client’s decision

Explanation:

just took the test

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Determine the amount of work done by the applied force when a 87 N force is applied to move a 15 kg object a horizontal
elena-s [515]

Answer:

391.5 J

Explanation:

The amount of work done can be calculated using the formula:

  • W = F║d
  • where the force is parallel to the displacement

Looking at the formula, we can see that the mass of the object does not affect the work done on it.

Substitute the force applied and the displacement of the object into the equation.

  • W = (87 N)(4.5 m)
  • W = 391.5 J  

The amount of work done on the object is 391.5 J in order to move it 4.5 meters with an applied force of 87 Newtons.

5 0
2 years ago
Read 2 more answers
An object of mass 300 g, moving with an initial velocity of 5.00i-3.20j m/s, collides with an sticks to an object of mass 400 g,
Alexus [3.1K]

Answer:

Velocity is 2.17 m/s at an angle of 9.03° above X-axis.

Explanation:

Mass of object 1 , m₁ = 300 g = 0.3 kg

Mass of object 2 , m₂ = 400 g = 0.4 kg

Initial velocity of object 1 , v₁ = 5.00i-3.20j m/s

Initial velocity of object 2 , v₂ = 3.00j m/s

Mass of composite = 0.7 kg

We need to find final velocity of composite.

Here momentum is conserved.

Initial momentum = Final momentum

Initial momentum = 0.3 x (5.00i-3.20j) + 0.4 x 3.00j = 1.5 i + 0.24 j kgm/s

Final momentum = 0.7 x v = 0.7v kgm/s

Comparing

1.5 i + 0.24 j = 0.7v

v = 2.14 i + 0.34 j

Magnitude of velocity      

       v=\sqrt{2.14^2+0.34^2}=2.17m/s

Direction,  

       \theta =tan^{-1}\left ( \frac{0.34}{2.14}\right )=9.03^0

Velocity is 2.17 m/s at an angle of 9.03° above X-axis.

7 0
3 years ago
A long point-object, mass = 1.0 kg, moves in a circular path at a radial distance = 0.5 m from the axis of rotation. What is the
Vinvika [58]

Answer:0.25\ kg-m^2

Explanation:

Given

mass of Point object m=1 kg

Distance r=0.5 m

Since mass is moving in circular path therefore every time mass is at distance of r from center .

Also Moment of Inertia tells about  the distribution of mass over the given region with respect to center of mass.

Therefore I=mr^2

I=1\times 0.5^2

I=0.25\ kg-m^2

5 0
3 years ago
A ________ detects the speed that a given device can handle and communicates with it at that speed
melisa1 [442]
Switch because look A switch detects the speed that given device can handle and communicates with it at that speed
4 0
3 years ago
The circuit below shows some of the circuity in a small toy robot. When the circuit is on, the robot moves its arms (the motor)
djyliett [7]

Answer:

dear can you provide the circuit of the robot

6 0
3 years ago
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