A human services professional has worked with a particular client for a couple of years. The client

1. How does an area’s weather differ from the area’s climate? (1 point). A.Weather involves temperature and precipitation and cl

makkiz [27]

1. "Weather is the area’s day-to-day conditions and climate is the area’s average conditions" is how an area’s weather differ from the area’s climate. The correct option among all the options given in the question is option "D".

2. All of the following factors contribute to Earth’s climate except longitude. The correct option among all the options given in the question is the second option.

4 0

2 years ago

Read 2 more answers

A compact car has a maximum acceleration of 2.0 m/s2 when it carries only the driver and has a total mass of 1100 kg . you may w

nadya68 [22]

According to Newton`s law. Force exerted by car,

$F = m a = 1100 kg \times 2 m/s^2 = 2200 \ N$

After adding an additional 400 kg of mass, the force will be same therefore the acceleration

$F = 2200 \ N = (1100 \ kg + 400 \ kg) a \\\\ a = \frac{2200 \ N}{1500 \ kg} = 1.47 \ m/s^2$

Thus, the acceleration after adding the masses is 1.47 \ m/s^2.

4 0

3 years ago

The average power dissipated by a resistor connected to a sinusoidal emf is 5.0 W.

loris [4]

I this is tricky one sec.. I would go with b

4 0

3 years ago

A three branch parallel circuit has resistors of 27 W, 56 W, and 15 W. What is the total resistance?

Mekhanik [1.2K]

Answer:8.2 Ω

Explanation:

I ASSUME you mean Ω (ohms) and not W(atts)

Re = 1/(1 / 27 + 1/56 + 1/15) = 8.2263329... ≈ 8.2 Ω

6 0

2 years ago

A stunt driver wants to make his car jump over 8 cars parked side by side below a horizontal ramp.

Genrish500 [490]

Answer:

a) Minimum speed must he drive off the horizontal ramp = 39.78 m/s

b) Minimum speed must he drive off the horizontal ramp with 7° above the horizontal = 23.93 m/s

Explanation:

a) The height of ramp = 1.5 meter

Horizontal distance he must clear = 22 meter

The car is having horizontal motion and vertical motion. In case of vertical motion the acceleration on the car is acceleration due to gravity.

We have equation of motion, $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In case of vertical motion initial velocity = 0 m/s, acceleration = 9.8 $m/s^2$ , we need to calculate time when displacement = 1.5 meter.

$1.5=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 0.553 seconds$

So the car has to cover a distance of 22 meter in 2.119 seconds.

So minimum speed required = 22/0.553 = 39.78 m/s

Minimum speed must he drive off the horizontal ramp = 39.78 m/s

b) When the take of angle is 7⁰ the vertical speed of car is not zero = V sin 7 = 0.122 V

So the in case of vertical motion we have initial velocity = 0.122 V, S = -1.5 meter( below ramp), acceleration = -9.8 $m/s^2$

Substituting

$-1.5=0.122V*t-\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2-0.122Vt-1.5=0$

In case of horizontal motion

Horizontal speed of car = V cos 7 = 0.993V

So it has to travel 22 meter in t seconds

0.993Vt = 22, Vt = 22.155 m

Substituting in the equation $4.9t^2-0.122Vt-1.5=0$

We will get $4.9t^2-0.122*22.155-1.5=0\\ \\ t = 0.926 seconds$

Speed required = 22.155/0.926 = 23.93 m/s

Minimum speed must he drive off the horizontal ramp with 7° above the horizontal = 23.93 m/s

7 0

3 years ago