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prisoha [69]
3 years ago
10

Talking to adults can be intimidating and uncomfortable if you do not yet feel like one. However, learning how to effectivelycom

municate with adults is an extremely important part of life as you grow older, especially while you are in college or join the workforce. The earlier you practice socializing and building relationships with adults, the more you learn how to do so, and the more comfortable you will be interacting with them as you grow older.
For this Call to Action assignment, use what you learned in the previous lessons to engage with adults who are not related to you and who you have not yet already established a comfortable relationship with. Think of an adult that you highly respect or would like to know better, and start a conversation with them. Be open and confident about what you think, how you feel, and who you are. Then, be open and respectful toward their responses. Try to engage with this person as best as you can during the conversation, and see how your relationship transforms.

Please write a 2-3 sentence summary of your conversation, as well as 2 sentences about how you felt about the interaction afterwards.
Physics
1 answer:
Korvikt [17]3 years ago
8 0

Answer: i didnt look at your question its to long

Explanation:

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When an object moves away from Earth, its light waves are stretched to a lower frequency, or longer wavelength, and thus we say
Gelneren [198K]
Your answer will be False because wavelengths are usually are use as sound waves. 
3 0
3 years ago
4. O/N 15/P11/Q11
anygoal [31]

Answer:

B) 4500 Pa

Explanation:

As pressure is force per unit area,

P = F/A

It stands to reason that the smallest pressure for a given force is when it is shared by the largest area.

The possible areas are

0.30(0.40) = 0.12 m²

0.30(0.50) = 0.15 m²

0.40(0.50) = 0.20 m²

The pressure when the face with the largest area (0.20 m²) is down is

P = 900 / 0.20 = 4500 N/m² or 4500 Pa

the other possible pressures would be

900/0.15 = 6000 Pa

900/0.12 = 7500 Pa

which are both larger than our solution.

5 0
3 years ago
How does a rubber rod become negativley charged trough friction/
natali 33 [55]

Answer: Answer below hope it helps

Explanation: How does a rubber rod become negatively charged through friction? It touches a negatively charged object, and protons move off of the rod. ... It is rubbed with another object, and electrons move onto the rod. It is rubbed with another object, and protons move off of the rod.

3 0
3 years ago
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two identical steel balls mounted on wooden posts initially have different amounts of charge, one with -14uC and the other with
GrogVix [38]

According to the Law of Conservation of Charge, the net charge remains constant. If both things have different charges, upon contact, they would share the charge equally. In this case, the total charge is -16μC. The final charge for each ball would be -8 μC.

7 0
3 years ago
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A stone is thrown from the top of a building 30m high. If it strikes the ground at an angle 45, with what speed was it thrown?
sasho [114]

Answer:

24.2 m/s

Explanation:

The stone strikes the ground at an angle of 45 degrees: this means that its vertical velocity is equal (in magnitude) to its horizontal velocity, in fact:

tan \theta = \frac{|v_y|}{v_x}\\tan 45^{\circ} = 1 \rightarrow |v_y| = v_x

The motion along the vertical direction is a uniformly accelerated motion, so we can find the final vertical velocity using the following suvat equation

v_y^2 -u_y^2 = 2as

where

v_y is the final vertical velocity

u_y = 0 is the initial vertical velocity (zero because the stone is thrown horizontally)

a=g=9.8 m/s^2 is the acceleration of gravity (we take downward as positive direction)

s = 30 m is the vertical displacement

Solving for vy,

v_y = \sqrt{u_y^2+2as}=\sqrt{0+2(9.8)(30)}=24.2 m/s

This means that the horizontal velocity is also 24.2 m/s: and since the horizontal velocity is constant during the whole motion (there is no acceleration in the horizontal direction), this means that the stone was thrown exactly at 24.2 m/s.

7 0
3 years ago
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