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prisoha [69]
3 years ago
10

Talking to adults can be intimidating and uncomfortable if you do not yet feel like one. However, learning how to effectivelycom

municate with adults is an extremely important part of life as you grow older, especially while you are in college or join the workforce. The earlier you practice socializing and building relationships with adults, the more you learn how to do so, and the more comfortable you will be interacting with them as you grow older.
For this Call to Action assignment, use what you learned in the previous lessons to engage with adults who are not related to you and who you have not yet already established a comfortable relationship with. Think of an adult that you highly respect or would like to know better, and start a conversation with them. Be open and confident about what you think, how you feel, and who you are. Then, be open and respectful toward their responses. Try to engage with this person as best as you can during the conversation, and see how your relationship transforms.

Please write a 2-3 sentence summary of your conversation, as well as 2 sentences about how you felt about the interaction afterwards.
Physics
1 answer:
Korvikt [17]3 years ago
8 0

Answer: i didnt look at your question its to long

Explanation:

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What layers on earth are considered liquids
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6 0
3 years ago
PLEASE HELP
blagie [28]
Assuming Adam is on earth g= 9.8 m/s and m= weight/ gravity = 667/9.8 = 68 kg
8 0
3 years ago
A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum
s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle=q=-2.74\times 10^{-6} C

Kinetic energy of particle=K_E=6.65\times 10^{-10} J

Initial time=t_1=6.36 s

Final potential difference=V_2=0.351 V

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

qV=K.E

Using the formula

2.74\times 10^{-6}V_1=6.65\times 10^{-10} J

V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V

Initial voltage=V_1=2.43\times 10^{-4} V

\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2

Using the formula

\frac{V_1}{V_2}=(\frac{6.36}{t})^2

\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}

t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}

t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}

t=241.7 s

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0
3 years ago
Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia
Gala2k [10]

Answer:

Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías

5 0
3 years ago
You can tell from reading this passage that -
Romashka-Z-Leto [24]

Answer: B or "diamonds are rare,valuable gems".

Explanation:

since the link does not show very much, I don't know if A is correct or not. D is incorrect because that  is an opinion. C is incorrect.

4 0
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