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Ksenya-84 [330]
3 years ago
15

The density of lead is 11.3 g/cm 3. What mass of lead is required to make a 1 cm 3 fishing sinker?

Physics
2 answers:
Luda [366]3 years ago
6 0

Answer:

11.3 g

Explanation:

Parameters given:

Density of lead, D = 11.3 g/cm^3

Volume of fishing sinker, V = 1 cm^3

Density is a characteristic of a substance and it is the measure of the mass per unit volume. Mathematically:

Density = \frac{mass}{volume} \\\\\\D = \frac{m}{v}

That means that mass is:

Mass = Density * volume

Therefore, the mass of lead needed to make the fishing sinker:

Mass = 11.3 * 1\\\\\\Mass = 11.3 g

Aliun [14]3 years ago
5 0

Answer:

11.3 g

Explanation:

given,

density of the lead = 11.3 g/cm³

volume = 1 cm³

mass of the lead = ?

we know,

density=\dfrac{mass}{volume}

mass = volume x density

mass = 1 x 11.3

mass = 11.3 g

hence, the mass of the lead is equal to 11.3 g

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Andre45 [30]

Answer:

The volume of water is 139 mL.

Explanation:

Due to the Law of conservation of energy, the heat lost by coffee is equal to the heat gained by the water, that is, the sum of heats is equal to zero.

Q_{coffee} + Q_{water} = 0\\Q_{coffee} = - Q_{water}

The heat (Q) can be calculated using the following expression:

Q=c \times m \times \Delta T

where,

c is the specific heat of each substance

m is the mass of each substance

ΔT is the difference in temperature for each substance

The mass of coffee is:

162mL.\frac{0.997g}{mL} = 162g

Then,

Q_{coffee} = - Q_{water}\\c_{c} \times m_{c} \times \Delta T_{c} = -c_{w} \times m_{w} \times \Delta T_{w}\\m_{c} \times \Delta T_{c} = -m_{w} \times \Delta T_{w}\\m_{w} = \frac{m_{c} \times \Delta T_{c}}{-\Delta T_{w}} \\m_{w}=\frac{162g \times (62.5 \°C - 94.6 \°C ) }{-(62.5 \°C - 25.0 \°C)} \\m_{w} = 139 g

The volume of water is:

139g.\frac{1mL}{0.997g} =139mL

7 0
4 years ago
An object which is dropped from a certain height has zero (0) initial velocity.
gavmur [86]

Answer:

0 m/s

Explanation:

if an object is dropped we know the initial velocity is zero when in free fall

8 0
3 years ago
The pressure in an automobile tire is 198 kpa at 300.0 k. at the end of a trip on a hot, sunny day, the pressure has risen to 22
Kamila [148]

We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

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T2 = 225 x 300 / 198

<span>T2 = 340.91 K</span>

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in which kind of radioactive decay would the number of protons in the resulting nucleus be more than in the initial nucleus?
9966 [12]

Answer:

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Explanation:

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2 years ago
A 1600 kg sedan goes through a wide intersection traveling from north to south when it is hit by a 2000 kg SUV traveling from ea
skad [1K]

Answer:

v = 11.1m/s

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