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Triss [41]
3 years ago
8

Suppose a set of test scores is approximately bell-shaped, with a mean of 66 and a range of 60.

Mathematics
1 answer:
luda_lava [24]3 years ago
8 0

Answer:

The lower limit is 36

Upper limit is 96

Standard deviation is 30

Step-by-step explanation:

Considering the range of the test score which is 60. i.e the difference between the largest and the smallest number is 60. The mean is 66 which is a measure of central tendency. That is it is at the centre of the distribution. Dividing 60 by 2 gives 30.

Adding 30 to the mean will indicate our upper limit i.e 30+66=96

Also, subtracting 30 from 66 will give the lower limit i.e. 66-30=36

The Distance between the range and the mean is the standard deviation

Which in this case is +30 or -30

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A, B, and C are collinear points, where B is between A and C. Find x if AB = x, BC = x + 6, and AC = 24. Then find the measures
Alekssandra [29.7K]

Answer:

AB = 9, BC = 15

Step-by-step explanation:

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\therefore AC = AB + BC\\\therefore 24 = x + x + 6\\\therefore 24 = 2x + 6\\\therefore 24 - 6 = 2x \\\therefore 18 = 2x \\ \therefore \:  \frac{18}{2}  = x \\  \therefore \: x = 9

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8 0
3 years ago
The sum of two numbers is 44. One number is 2 more than twice the other. Write a system of equations that defines this situation
hram777 [196]
System: x + y = 44; x = 2y + 2

Solve with substitution: x = 30; y = 14



x + y = 44
x = 2y + 2

Substitute 2y + 2 for x

2y + 2 + y = 44

3y + 2 = 44

Subtract 2 on both sides.

3y = 42

y = 14

Now substitute back in.

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Subtract 14 on both sides.

x = 30
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3 years ago
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