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Sophie [7]
3 years ago
9

Spam filters in an email program are similar to hypothesis tests in that there are two possible decisions and two possible reali

ties and therefore two kinds of errors that can be made. The hypotheses can be considered as:
H0: Incoming email message is legitimate.
Ha: Incoming email message is spam.

Suppose an incoming legitimate message is flagged by the spam filter and sent to the spam folder. What type of error did the spam filter make?

Select one:

a. Type II error
b. No error was made
c. Type I error
Mathematics
1 answer:
Eva8 [605]3 years ago
7 0

Answer:

Option C) Type I error

Step-by-step explanation:

We are given the following in the question:

H_0:\text{Incoming email message is legitimate.}\\H_a: \text{Incoming email message is spam.}

Type I error:

  • It is also known as false positive.
  • It is the rejection of a true null hypothesis.

Type II error:

  • It is known as false positive.
  • It is the acceptance of a false alternate hypothesis.

An incoming legitimate message is flagged spam by a spam filter.

Thus, a true null hypothesis that the message is legitimate is rejected and the message is send to spam folder.

Thus, spam filter made a

Option C) Type I error

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Answer:

The probability that a part was manufactured on machine A is 0.3

Step-by-step explanation:

Consider the provided information.

It is given that Half of a set of parts are manufactured by machine A and half by machine B.  

P(A)=0.5

Let d represents the probability that part is defective.

Ten percent of all the parts are defective.

P(d) = 0.10

Six percent of the parts manufactured on machine A are defective.

P(d|A)=0.06

Now we need to find the probability that a part was manufactured on machine A, and given that the part is defective :

P(A|d) =\frac{P(A \cap d)}{P(d)}

P(A|d) =\frac{P(d|A)\times P(A)}{P(d)}\\P(A|d)= \frac{0.06\times 0.5}{0.10}

P(A|d)= 0.3

Hence, the probability that a part was manufactured on machine A is 0.3

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On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John
insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

     $H_{max}=\frac{v^2}{2g}$

     $H_{max} = \frac{(48)^2}{2 \times 12}$

               = 96 ft

b). Time he can stay in the air before hitting the ground is

   $T=\frac{2v}{g}$

  $T=\frac{2 \times 48}{12}$

     = 8 seconds

c).  Considering upward motion as positive direction.

     v = u + at

We find the time taken to reach the maximum height by taking v = 0.

     v = u + at

     0 = 16 + (12) t

     $t=\frac{16}{12}$

        $=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t =  $=\frac{4}{3} \ s$  , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$  feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

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3 years ago
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