1. The given rectangular equation is
.
We substitute
.

Divide through by 



2. The given rectangular equation is:

This is the same as:

We use the relation 
This implies that:



3. The given rectangular equation is:

This is the same as:
We use the relation
and 
This implies that:

Divide through by r


4. We have 
We substitute
and 

This implies that;



5. We have 
We substitute
and 

This implies that;



A way you can show work is just not use the commas then subtract then put the commas in when you're done. And, if the bigger number isn't as big or has as many numbers behind the decimal as the first one, add a zero at the end.
> multiply the second equation by 2 and add it to the first equation.
2(-6x - 7y = -10)
-12x -14y = -20
8x + 14y = 4
-12x - 14y = -20
--------------------
- 4x + 0 = - 16
x = -16/-4
x = 4
> use x = 4 in either equation to find y
8(4) + 14y = 4
32 + 14y = 4
14y = 4 - 32
14y = -28
y = -28/14
y = -2
First, find the probability of each event:
1) the probability that the spinner will land on a 7.
Since the spinner is split 4 equal sections and there is only 1 sector with 7, we can say the probability of getting a 7 is 1/4 as there is only 1 of 7 out of the total of 4 sections.
<em>and</em>
2) the probability that the spinner will land on B.
Since the spinner is split into 3 equal sections, and there is only 1 sector for B, we can say the probability of getting B is 1/3.
To find the probability of 2 events, we need to multiply the two probabilities.
1/4*1/3 = 1/12
So the answer is 1/12.
The answer is 3 because if you were to round 2.9 the next whole up from that is 3