The information given to us shows that triangles XYZ and JKL is not enough to prove they are congruent by AAS, ASA, nor SAS.
<h3>The Triangle Congruence Theorems</h3>
- Two triangles are congruent by the AAS congruence theorem if they both have two pairs of congruent angles and a pair of congruent non-included sides.
- Two triangles are congruent by the ASA congruence theorem if they both have two pairs of congruent angles and a pair of congruent included sides.
- Two triangles are congruent by the SAS congruence theorem if they both have two pairs of congruent sides and a pair of congruent included angles.
Thus, the information given to us shows that triangles XYZ and JKL is not enough to prove they are congruent by AAS, ASA, nor SAS.
Learn more about triangle congruence theorem on:
brainly.com/question/2579710
A. The relationship of <7 and <8 are that they are vertical angles, and are congruent.
B. Since vertical angles are congruent, you can form an equation where the two measurements equal each other.
C. 5y-29=3y+19 then plug y into your equation: 5*24-29=91
2y=48 and so: <7 = 180-91=89 (and since <8 is congruent)
y=24 <8 also equals 89
Your second problem:
complementary are two angles that add up to 90 degrees.
<B=x, <A=2x
2x+x=90
3x=90
x=30 so: <B=30 degrees, <A=60 degrees
Your third problem:
1. Since A and B are parallel, angle 3x+7 and angle 4x+5 are same-sided exterior angles. That means that they both add up to 180 degrees. So if you should add the two and make it equal 180
2. 3x+7+4x+5=180
7x+12=180
7x=168
x=24
3. <6 is a corresponding angle with angle 3x+7, meaning that they are congruent. So plug x into 3x+7: 3*24+7=79 and since <6 is congruent to 3x+7, <6=79 degrees
Answer:
37 9/20
Step-by-step explanation:
=24/20 thus the answer is 1.2
[x-1]=5x+10
We have two equations:
1) x-1=5x+10
x-1=5x+10
x-5x=10+1
-4x=11
x=-11/4
2) x-1=-(5x+10)
x-1=-(5x+10)
x-1=-5x-10
x+5x=-10+1
6x=-9
x=-9/6=-3/2
we have two possible solutions:
solution₁; x=-11/4
solution₂: x=-3/2
we check it out:
1) x=-11/4
[x-1]=5x+10
[-11/4 - 1]=5(-11/4)+10
[(-11-4)/4]=-55/4 + 10
[-15/4]=(-55+40) /4
15/4≠-15/4 This solution don´t work.
2) x=-3/2
[x-1]=5x+10
[-3/2 - 1]=5(-3/2)+10
[(-3-2)/2]=-15/2 + 10
[-5/2]=(-15+20)/2
5/2=5/2; this solution works.
Therefore:
Answer: x=-3/2.
