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gizmo_the_mogwai [7]
3 years ago
14

Ls Figure A'B'C'D' a translation of Figure ABCD? (Click in the picture to see the rest

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

Answer:D

Step-by-step explanation: It is none of them because it is translated up one unit and then reflected across the y axis.

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The lengths are \frac{5}{6} \frac{5}{12} and \frac{1}{3}
finding the LCM we get
\frac{10,5,4}{12}
arranging them 
 \frac{1}{3} \frac{5}{12} and \frac{5}{6}
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3 years ago
Determine the following<br>quadratic equations have real<br>roots<br><br>1) 3x² - √2x-√3​
IceJOKER [234]

Step-by-step explanation:

√3 x² - 2x - √3 = 0

√3 x² - 3x + x - √3 = 0

√3 x(x - √3) + 1(x - √3) = 0

(x - √3 ) (√3 x + 1) = 0

x - √3 = 0 , √3 x +1 = 0

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3 years ago
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3 years ago
Raoul saves $14.50 each month for 3 months. He puts his money in the bank and earns $0.33 interest . Hector puts \$3.60 e each w
Norma-Jean [14]

Answer:

$0.63

Step-by-step explanation:

Raoul saves $14.50 each month for 3 months. Total amount saved is 14.50 * 3 = $43.50

He earned an interest of $0.33.

The total amount of money he has is thus: 43.50 + 0.33 = $43.83

Hector puts $3.60 each week for 12 weeks. Total amount save by Hector is thus 3.60 * 12 = $43.2

Now we are asked to get how much money Raoul has. To get this, we simply subtract the amount of money Hector has from that of Raoul

That would be 43.83 - 43.2 = $0.63

4 0
3 years ago
A scientist needs 10 liters of a 20% acid solution for an experiment, but she has only a 5% solution and a 40% solution. To the
tamaranim1 [39]

Answer:

The volume of 40% solution= 4.3L

The volume of 5% solution= 10L - 4.3L= 5.7L

Step-by-step explanation:

From the given information:

Let consider  x to be the of volume 40% solution

therefore the volume of 5% is said to be:

10 L= 40% solution volume + 5% solution volume

10 L= (x + 5%) solution volume

making 5% solution volume the subject; we have

5% solution volume= 10 L - x

To estimate the value of the volume, we now have:

Volume  of 20% × Concentration of  20%= (Volume of 40%  × concentration40%) + (Volume of 5% × Concentration of 5% )

∴

10L  ×  20%= (x) L × 35% + 10 L × 5%

(x) L × 35 = 10L × 20 - 10 L × 5 = 10 L × 15

x L = 10L \times \dfrac{15}{35}

x = 4.28 L

x \simeq 4.3L

∴

The volume of 40% solution= 4.3L

The volume of 5% solution= 10L - 4.3L= 5.7L

8 0
3 years ago
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