Answer:
ARE U STILL GIVING BRAINLIEST?
Explanation:
Answer:
Percent yield = 50%
Explanation:
Given data:
Mass of CH₄ = 16 g
Mass of O₂ = 32 g
Mass of CO₂ = 11 g
Percent yield of CO₂ = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of CH₄:
Number of moles = mass/ molar mass
Number of moles = 16 g /16 g/mol
Number of moles = 1 mol
Number of moles of O₂:
Number of moles = mass/ molar mass
Number of moles = 32 g /32 g/mol
Number of moles = 1 mol
Now we will compare the moles of CO₂ with both reactant.
O₂ : CO₂
2 : 1
1 : 1/2×1= 0.5 mol
CH₄ : CO₂
1 : 1
Number of moles of CO₂ produced by oxygen are less so it will limiting reactant.
Theoretical yield:
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 0.5 mol × 44 g/mol
Mass = 22 g
Percent yield:
Percent yield = actual yield / theoretical yield × 100
Percent yield = 11 g/ 22 g × 100
Percent yield = 50%
Answer:
3.45 moles Li contains 2.08 × 10 (to the power of)24 atoms .
Explanation:
The relationship between atoms and moles is:
1 mole atoms =
6.022 × 10 (to the power of)23
atoms
In order to determine how many atoms occupy a given number of moles, multiply the given moles by
6.022 × 10 (to the power of)23
atoms/mole
.
In the case of 3.45 moles lithium (Li):
3.45 mol Li × 6.022 × 10 (to the power of)23 atoms Li/ 1 mol Li =
2.08 × 10 (to the power of)24
atoms Li rounded to three
Answer:
E = hV
Explanation:
Hello,
Photo electric effect theory was borne out the the confusing if light was either a particle or a wave. However Albert Einstein came up with a theory that light was a particle and each particle carry a certain amount of energy referred to as photons.
He used Max Planck's idea and theorized that since light is made up of photon, when each photon comes in contact with the surface of a metal, the energy is transferred to the electron.
E = hv
E = energy of the photons
h = Planck's constant = 6.626×10⁻³⁴Js
v = frequency of the photon in Hz
Explanation:
The question involves converting from one unit (Kilometres) to another unit (Astronomical unit)
The relationship between both units is given as;
1 Km = 6.68459e-9 Au
Kulper belt
6.5 billion km = 6.5e9 Km
1 Km = 6.68459e-9 Au
6.5e9 Km = x
Solving for x;
x = 43.45 Au
Alpha Centauri
44 trillion km = 4.4e13
1 Km = 6.68459e-9 Au
4.4e13 km = x
Solving for x;
x = 294121.83 Au
