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Viefleur [7K]
3 years ago
14

Anyone (cool, funny, middle school) wanna start a conversation?

Chemistry
2 answers:
pychu [463]3 years ago
5 0

Answer:

sure

Explanation:

what's up

nadya68 [22]3 years ago
3 0

Answer:

Im down, Im in 7th

Explanation:

sure hi lol

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A gas that was heated to 150 Celsius has a new volume of 1587.4 L. What was its volume when its temperature was 100 Celsius?
sdas [7]

Answer:

\boxed {\boxed {\sf 1058.3 \ L}}

Explanation:

We are asked to find the new volume of a gas after a change in temperature. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula for this law is:

\frac {V_1}{T_1}= \frac{V_2}{T_2}

The gas was heated to 150 degrees Celsius and had a volume of 1587.4 liters.

\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{T_2}

The temperature was 100 degrees Celsius, but the volume is unknown.

\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{100 \textdegree C}

We are solving for the volume at 100 degrees Celsius, so we must isolate the variable V₂. It is being divided by 100°C and the inverse of division is multiplication. Multiply both sides of the equation by 100°C.

100 \textdegree C *\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{100 \textdegree C} * 100 \textdegree C

100 \textdegree C *\frac {1587.4 \ L }{150 \textdegree C} = V_2

The units of degrees Celsius cancel.

100  *\frac {1587.4 \ L }{150 } = V_2

100 *10.58266667  \ L = V_2

1058.266667 \ L = V_2

The original measurement of volume has 5 significant figures, so our answer must have the same. For the number we calculated, that is the tenth place. The 6 in the hundredth place to the right tells us to round to 2 up to a 3.

1058.3 \ L = V_2

The volume of the gas at 100 degrees Celsius is approximately <u>1058.3 liters.</u>

6 0
3 years ago
Types of forces lab report
denpristay [2]
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4 0
2 years ago
What is nourishing for a seed of a plant?
fiasKO [112]

making sure that it has all the necessary conditions to become a big plant:

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3 0
2 years ago
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Calculate the moles of argon gas at STP in 33 L. Round answer to 2 significant figures.
babymother [125]

Answer:

1.5 mol

Explanation:

Step 1: Given data

  • Volume of argon gas: 33 L
  • Standard temperature: 273.15 K
  • Standard pressure: 1 atm

Step 2: Calculate the moles corresponding to 33 L of argon at standard temperature and pressure (STP)

At STP, 1 mole of argon gas occupies 22.4 L.

33 L × 1 mol/22.4 L = 1.5 mol

4 0
3 years ago
Write the symbolic notation of an isotope of an element having 8 protons, 8 electrons, and 9 neutrons
Mariulka [41]
The number of protons uniquely identifies the element. This is not on the periodic table. Isotopic notationincludes the atomic number and the mass number. 8 17 This isotope of oxygen has 8 protons (atomic number), 8 electrons and 9 neutrons
7 0
3 years ago
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