Answer: The bonds are intermediate between double and single bonds
Explanation:
A closer look at the diagram below shows that the bonds in sulphur IV oxide are intermediate between double and single bonds. Hence they do not have the exact bond angle of single bonds. This is why the bond angle is not exactly 120°. There are two resonance structures in the diagram that clearly show this point.
The answer will be 12 nitrogen or N2 will be produced because if you changed the coefficient to 12 on the reactant side and distribute, the nitrogen would be 12 when distributed and what happens on one side has to equal to the other side, which is the product side.
-Are the most used in daily life and basic human needs
(such as oxygen,nitrogen,carbon, etc)
For this reaction to proceed, the following bond breaking should occur:
*one C-H bond
* one Cl-Cl bond
After, the following bond formations should occur:
*one C-Cl bond
*one H-Cl bond
Now, add the bond energies for the respective bond energies which can be found in the attached picture. For bond formations, energy is negative. For bond breaking, energy is positive.
ΔHrxn = (1)(413) + (1)(242) + 1(-328) + 1(-431) =
<em>-104 kJ</em>