Answer:
sec^2(x)
Tell me if I'm correct or wrong. If I'm correct, plz mark me brainliest!
Answer:
Y=3x+12 (its the first option)
Answer:
The dimensions of the driveway are 21 ft x 47 ft, which is option "D" in your list of possible answers
Step-by-step explanation:
Notice that the length "L" of the driveway can be written in terms of its width as:
L = 2 w + 5
based on the given information.
Please see the attached diagram to understand the geometry of the problem, and what the area of the brick walkway involves (depicted in brick color) as the addition of the area of two rectangles:
1) one of length L= 2 w + 5 (w being the width of the driveway - depicted in grey) times 3 feet (the width of the brick walkway
and the other one:
2) w + 3 times 3
Therefore the total area of the brick walkway is given by the formula:
(2 w + 5) * 3 +(w + 3) * 3 = 213 square feet
Now we can solve for "w" in the above equation:
6 w + 15 + 3 w + 9 = 213
9 w + 24 = 213
9 w = 213 - 24
9 w = 189
w = 189/9
w = 21 feet
We can now solve for the L of the driveway, using the first formula we created:
L = 2 w + 5
L = 2 (21) + 5
L = 42 + 5
L = 47 feet
Therefore the driveway's width is w = 21 feet
and its length is L = 47 feet
Answer:
A rectangle with a length of 6 and width of 3. A rectangle with a length of 4 and width of 2.
Step-by-step explanation:
A rectangle with a length of 6 and width of 3. A rectangle with a length of 4 and width of 2 because the two are both examples of the length being two tiems the width.
Answer:
Step-by-step explanation:
Take a triangle ABC, in which AB=AC.
Construct AP bisector of angle A meeting BC at P.
In ∆ABP and ∆ACP
AP=AP[common]
AB=AC[given]
angle BAP=angle CAP[by construction]
Therefore, ∆ABP congurent ∆ACP[S.A.S]
This implies, angle ABP=angleACP[C.P.C.T]