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sveta [45]
4 years ago
7

Simplify each sum(5m^4+7-m^3)+(7m^3-7m^2+1)​

Mathematics
2 answers:
lapo4ka [179]4 years ago
4 0

Step-by-step explanation:

5m4 + 7 - m3 + 7m3 - 7m2 + 1

Solving like terms

5m4 + 6m3 - 7m2 + 8

Tom [10]4 years ago
3 0
The answer Is :=5m^4+6m^3-7m^2+8
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given a rectangular has a length of 58.5 m and widht of 45 m. Draw a diagram with scake if givrn scale drawing is 1 cm:9m​
Vera_Pavlovna [14]

Answer:

In picture

Step-by-step explanation:

Brainliest please

5 0
3 years ago
Nate's savings account for the business had $12.10 more at the end of the year than the $252 it had at the begining of the year.
Ulleksa [173]
4.58% is the answer. You need to add the $12.10 to $252 to get the total. 252x100%=2500÷264.10 then subtract the answer from 100.
8 0
4 years ago
20 POINTS!!!!!
harina [27]

Answer:

20.  300π m³

21.  457 1/3 π cm³

Step-by-step explanation:

20. r = 10 ÷ 2 = 5

V = 5² × 12 × π = 25 × 12π=300π m³

21. r = 14 ÷ 2 = 7

V = \frac{4}{3} \pi 7x^{3}

V = 457 1/3 π cm³

4 0
4 years ago
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telo118 [61]
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6 0
3 years ago
Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed
vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 11-1 = 10.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have T = 1.812

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{4}{\sqrt{11}} = 1.2060

Now, we multiply T and s

M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

L = 97 + 2.19 = 99.19 = 99.2cm

So

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0
3 years ago
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