Answer:
The Answer should be Endothermic reaction
Explanation:
Reactions in which energy is absorbed are called Endothermic reactions.
Beef and cheddar I believe!!!
The volume of a gas that is required yo react with 4.03 g mg at STP is 1856 ml
calculation/
- calculate the moles of Mg used
moles=mass/molar mass
moles of Mg is therefore=4.03 g/ 24.3 g/mol=0.1658 moles
- by use of mole ratio of Mg:O2 from the equation which is 2:1
the moles 02=0.1679 x1/20.0829 moles
- at STP 1 mole of a gas= 22.4 l
0.0895 moles=? L
- =0.0895 moles x22.4 l/ 1 mole=1.8570 L
into Ml = 1.8570 x1000=1856 ml approximately to 1860
Answer:
1.0975 atm.
Explanation:
<em>According to Boyle’s Law:</em> "
At constant temperature , the volume of a given quantity of a gas varies inversely with its pressure".
P α 1/V.
<em>∴ P₁V₁ = P₂V₂.</em>
P₁ = 4.39 atm, V₁ = 0.5 L.
P₂ = ??? atm, V₂ = 2.0 L.
<em>∴ P₂ = P₁V₁/V₂</em> = (4.39 atm)(0.5 L) / (2.0 L) = <em>1.0975 atm.</em>
Answer:
moles of CO2 can be produced from a reaction of 10.0 moles C2H6
Explanation:
In this reaction -
2 moles of C₂H6 produces four molecules of Carbon dioxide (CO2)
So 1 mole of C₂H6 will produce 
moles of Carbon dioxide (CO2)
Thus, 10 moles of C₂H6 will produce 
moles of Carbon dioxide (CO2)
