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loris [4]
3 years ago
7

Plzz someone help me ASAP!

Chemistry
1 answer:
irina1246 [14]3 years ago
3 0

The greater the friction, or rubbing, between particles in any fluid, the higher the viscosity. A fluid with a high viscosity has a large amount of internal friction. As the temperature of a gas increases, friction increases, and so the viscosity of the gas increases. The warmer the gas, the slower it flows.
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The equilibrium constant, K, for the following reaction is 5.10X10 at 548 K. NH_CH(s) 2 NH3(E) + HC1(2) Calculate the equilibriu
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Answer:

The equilibrium concentration of HCl is 0.01707 M.

Explanation:

Equilibrium constant of the reaction = K_c=5.10\times 10^{-6}

Moles of ammonium chloride = 0.573 mol

Concentration of ammonium chloride = \frac{0.573 mol}{1.00 L}=0.573 M

     NH_4HCl(s)\rightleftharpoons 2 NH_3(g) + HCl(g)

Initial:            0.573     0           0

At eq'm:      (0.573-x)   x           x

We are given:

[NH_4Cl]_{eq}=(0.573-x)

[HCl]_{eq}=x

[NH_3]_{eq}=x

Calculating for 'x'. we get:

The expression of K_{c} for above reaction follows:

K_c=\frac{[HCl][NH_3]}{[NH_4Cl]}

Putting values in above equation, we get:

5.10\times 10^{-6}=\frac{x\times x}{(0.573-x)}

2.9223\times 10^{-6}-5.10x\times 10^{-6}=x^2

x^2-2.9223\times 10^{-6}+(5.10\times 10^{-6})x=0

On solving this quadratic equation we get:

x = 0.01707 M

The equilibrium concentration of HCl is 0.01707 M.

3 0
3 years ago
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