All categories

3 years ago

Explain the flow of electrons in p-type semiconductors and why it looks like a flow of positive charges.

Physics

2 answers:

Morgarella [4.7K]3 years ago

5 0

Answer:

In p type of semiconductors we know that impurity of trivalent valency is added into the pure semiconductors. Due to this trivalent impurity the bond is made between the atoms in such a way that it will show a vacant space in its bonding around an atom.

Due to the bonding of the trivalent valency of atom with the pure semiconductor atom it form a bond in which 3 electrons will share completely while in fourth valency it shows a vacancy.

This vacant space is known as holes. which will be filled by shared electrons as it is a lower energy state in the space.

Now when we see the charge sharing in this then here the vacant space is filled due to the shifting of valance electrons in the bonds. As electron will fill the position of hole then it will create the vacancy at the previous position of the electron and this continues till the vacancy is filled by different electron.

As we can see that holes are created at different positions due to flow of electrons then we can relate is to the flow of positive charge as its motion is opposite the flow of electrons.

Svetach [21]3 years ago

4 0

One of the key terms in describing the flow of electrons in p-type semiconductors is the concept of holes. Holes are generally produced when an electron is gone missing when its moves from a lower potential to a higher potential. What is left behind the process is a term called "hole."

You might be interested in

At which of the following temperature and pressure levels would a gas be most likely to follow the ideal gas law? A. 0 K and 100

bulgar [2K]

The Ideal Gas Law makes a few assumptions from the Kinetic-Molecular Theory. These assumptions make our work much easier but aren't true under all conditions. The assumptions are,

1) Particles of a gas have virtually no volume and are like single points.
2) Particles exhibit no attractions or repulsions between them.
3) Particles are in continuous, random motion.
4) Collisions between particles are elastic, meaning basically that when they collide, they don't lose any energy.
5) The average kinetic energy is the same for all gasses at a given temperature, regardless of the identity of the gas.

It's generally true that gasses are mostly empty space and their particles occupy very little volume. Gasses are usually far enough apart that they exhibit very little attractive or repulsive forces. When energetic, the gas particles are also in fairly continuous motion, and without other forces, the motion is basically random. Collisions absorb very little energy, and the average KE is pretty close.

Most of these assumptions are dependent on having gas particles very spread apart. When is that true? Think about the other gas laws to remember what properties are related to volume.

A gas with a low pressure and a high temperature will be spread out and therefore exhibit ideal properties.

So, in analyzing the four choices given, we look for low P and high T.

A is at absolute zero, which is pretty much impossible, and definitely does not describe a gas. We rule this out immediately.

B and D are at the same temperature (273 K, or 0 °C), but C is at 100 K, or -173 K. This is very cold, so we rule that out.

We move on to comparing the pressures of B and D. Remember, a low pressure means the particles are more spread out. B has P = 1 Pa, but D has 100 kPa. We need the same units to confirm. Based on our metric prefixes, we know that kPa is kilopascals, and is thus 1000 pascals. So, the pressure of D is five orders of magnitude greater! Thus, the answer is B.

6 0

4 years ago

The diffusion coefficients for species A in metal B are given at two temperatures: T (°C) D (m2/s) 1020 8.01 × 10-17 1290 7.86×

Solnce55 [7]

Explanation:

Below is an attachment containing the solution.

5 0

3 years ago

A supersonic jet is at an altitude of 14 kilometers flying at 1,500 kilometers per hour toward the east. At this velocity, how f

Kaylis [27]

Answer:

The jet will fly 2400 km.

Explanation:

Given the velocity of the jet flying toward the east is 1,500 kmph toward the east.

We need to find the distance covered in 1.6 hours.

In our problem we are given speed and time, we can easily determine the distance using the following formula.

$Distance=Speed\times Time$

$Distance=1500\times 1.6=2400\ km$

So, the supersonic jet will travel 2400 km in 1.6 hours toward the east from its starting point.

3 0

4 years ago

Which scientist proved experimentally that a shadow of the circular object illuminated 18. with coherent light would have a cent

Zina [86]

Answer:

Your answer is( D) - Arago

8 0

3 years ago

A cart moving at 10 m/s is brought to a stop by the force plotted in the force-time graph shown here. Find the impulse and the a

Elena L [17]

Answer:

Impulse = 88 kg m/s

Mass = 8.8 kg

Explanation:

<u>We are given a graph of Force vs. Time. Looking at the graph we can see that the Force acts approximately between the time interval from 1sec to 4sec. </u>

Newton's Second Law relates an object's acceleration as a function of both the object's mass and the applied net force on the object. It is expressed as:

$F=ma$ Eqn. (1)

where

$F$ : is the Net Force in Newtons ( $N$ )

$m$ : is the mass ( $kg$ )

$a$ : is the acceleration ( $m/s^2$ )

We also know that the acceleration is denoted by the velocity ( $v$ ) of an object as a function of time ( $t$ ) with

$a=\frac{v}{t}$ Eqn. (2)

Now substituting Eqn. (2) into Eqn. (1) we have

$F=m\frac{v}{t}\\ \\Ft=mv$ Eqn. (3)

However since in Eqn. (3) the time-variable is present, as a result the left hand side (i.e. $Ft$ is in fact the Impulse $J$ of the cart ), whilst the right hand side denotes the change in momentum of the cart, which by definition gives as the impulse. Also from the graph we can say that the Net Force is approximately ≈ $22N$ and $t=4 sec$ (thus just before the cut-off time of the force acting).