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Shalnov [3]
3 years ago
12

A roofer drops a nail that hits the ground traveling at 26 m/s. How fast was the nail traveling 1 second before it hits the grou

nd?
Physics
1 answer:
RoseWind [281]3 years ago
6 0

vf = vi + at 

vf – vi = at<span>

<span>vi= 0, vf=26  and afor nil = 9.8m/s2</span></span>

26 = 9.8t

t =<span> 26 / 9.8 = 2.65 s
Now we know the total time, so we can calculate the time 1 second before it hit the ground. 

<span>= 2.65 -1 = 1.65s

<span>Now again using the same equation, vf = vi+at, we can find vf
vi = 0, a = 9.8 t=1.65</span></span></span>

vf = 0 + 9.8(1.65) = 16.17 m/s<span>
</span><span>So, the nail is traveling with the speed of 16.17m/s 1 second before it hits the ground.</span>

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