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3 years ago

An automobile factory,1849 parts are made in 4 hours.what is the average rate at which parts are made per hour?

Mathematics

2 answers:

MAXImum [283]3 years ago

7 0

Answer:

There are 462.25 parts being made per hour

Step-by-step explanation:

Step 1: Make an equation

An automobile factory, 1849 parts are made in 4 hours.

1849 / 4 = x

Step 2: Solve

1849 / 4 = x

462.25 = x

Answer: There are 462.25 parts being made per hour

LUCKY_DIMON [66]3 years ago

5 0

To find the hourly rate the parts are made, just divide.

1,849 / 4 = 462.25 parts made per hour.

Best of Luck!

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I WILL MARK BRAINLIEST :]

Maurinko [17]

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3 years ago

A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is

scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=360000$ represent the mean for the downtown restaurant

$\bar X_{2}=340000$ represent the mean for the freeway restaurant

$s_{1}=50000$ represent the sample standard deviation for downtown

$s_{2}=40000$ represent the sample standard deviation for the freeway

$n_{1}=36$ sample size for the downtown restaurant

$n_{2}=36$ sample size for the freeway restaurant

t would represent the statistic (variable of interest)

$\alpha=0.05$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis: $\mu_{1}\leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level $\alpha=0.05$ and $\alpha/2=0.025$ we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is $t_{1-\alpha/2}=1.66$

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874$

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

$p_v =P(t_{70}>1.874)=0.033$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0

3 years ago

Help please, will mark brainliest

mario62 [17]

Answer:

Step-by-step explanation:

LET ORANGES=X

PEARS ARE 3 TIMES =3X

LET CHILDREN=Y

IF WE GIVE 5 ORANGES PER CHILD WE NEED 5Y ORANGES.SO THIS =X

X=5Y........................I

IF WE GIVE 8 PEARS PER CHILD WE NEED 8Y PERARS...THERE ARE STILL 21 PEARS LEFT OUT AFTER THIS THAT IS

8Y+21=3X....................II

SUBSTITUTING FOR X FROM EQN.I..

8Y+21=3*5Y

15Y-8Y=21

7Y=21

Y=3

X==5Y=5*3=15..

SO CHILDREN =3

ORANGES=15

PEARS=3*15=45

THANKYOU AND PLEASE AMRK IT BRAINLIEST

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3 years ago

Farmer Brown is prepping his circular garden for the new spring/summer season of vegetables. The garden has to be larger than 25

d1i1m1o1n [39]

Answer:

The area is 78.5, the farmer does have enough space to plant his vegetables

Step-by-step explanation:

To find the area, you need to use the formula, A=πr², (make sure the diameter is turned into the radius by dividing by 2, in this case, it's 5 as the radius)

Plug in your numbers, A= 3.14(5)²

A= 3.14(25)

The area is 78.5

So the farmer does have enough space to plant his vegetables since 78.5 is greater than 25

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3 years ago