I dont know man you gotta ask a question
Answer:
see explaination
Step-by-step explanation:
Using the formulla that
sum of terms number of terms sample mean -
Gives the sample mean as \mu=17.954
Now varaince is given by
s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97
and the standard deviation is s=\sqrt{9.97}=3.16
b) The standard error is given by
\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45
c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1
Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88
d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05
Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96
or a number which is less than 15.83-1.5(4.05)=9.76
As there is no such number so the given sample has no outliers
Answer:
a.114.4kg
b. 486kg
Step-by-step explanation:
Firstly , we want to know the value with which the apples weigh more than the oranges
To calculate this, we simply subtract the weight of the oranges from that of the apple
Mathematically, that would be ;
300.2-185.8 = 114.4kg
The total weight of the things bought is calculated by adding both weights together
That would be 185.8 + 300.2 = 486 kg
If you do 130 divided by 7, you get 18 with a remainder of 4. The answer is 18 cards on each page.
