Plz help me with part 48
1 answer:
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Answer: 0.9726
Step-by-step explanation:
Let x be the random variable that represents the distance the tires can run until they wear out.
Given : The top-selling Red and Voss tire is rated 50,000 miles, which means nothing. In fact, the distance the tires can run until they wear out is a normally distributed random variable with a 67,000 miles and a
5,200 miles.
Then , the probability that a tire wears out before 60,000 miles :
[using p-value table for z]
Hence, the probability that a tire wears out before 60,000 miles= 0.9726
notice that the denominator can be factored into (x-3)(x+3).
Now you can cross out (x - 3) from the numerator and denomiantor resulting in a simplified fraction of
Plug the limit value (which is 3) into the simplified fraction.
Answer: