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iren [92.7K]
3 years ago
8

PLEASE HELP ME I REALLY NEED HELP!

Mathematics
1 answer:
rewona [7]3 years ago
6 0
Equation 1 is:
y=2x+4

Equation 2 is:
y=-3x-2

Equation 3 is:
y=0.5x+3.5

Equation 4 is:
y=-0.4x+6

There is a website called desmos: (desmos.com)
Just go onto there and type the equations into the system.
The website will graph them for you :)
You might be interested in
Use the distributive property to create an expression equivalent to the one below. 5(7x+6y)
LUCKY_DIMON [66]

Answer:

35x+30y

Step-by-step explanation:

5×7x=35x

5×6y=30y

35×+30 y

3 0
2 years ago
Read 2 more answers
Lori rented a car for one day. The daily rental rate was $12.50 plus 25 cents per mile. The total cost of her rental was $46. Ho
Leona [35]

Answer:

The number of miles Lori drive be 134 miles .

Step-by-step explanation:

Let us assume that the number of miles Lori be x.

As given

Lori rented a car for one day.

The daily rental rate was $12.50 plus 25 cents per mile.

As 1 dollar = 100 cent

1\ cent = \frac{1}{100}\ dollar

25\ cent = \frac{25}{100}\ dollar

25\ cent = 0.25\ dollar

As given

The total cost of her rental was $46.

Than the equation becomes

46 = 12.50 + 0.25x

46 - 12.50 = 0.25x

33.5 = 0.25x

x = \frac{33.5}{0.25}

x = 134 miles

Therefore the number of miles Lori drive be 134 miles .


6 0
3 years ago
If f(6) if f(x)=x^2 / 3 + x
MakcuM [25]

Answer:

1) If the function is f(x)=\frac{x^{2}}{(3+x)}, f(6)=4

2) If the function is f(x)=x^{(2/3)}+x, f(6)=9.30

3) If the function is f(x)=\frac{x^{2}}{3}+x, f(6)=18

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

f(6) means that you must substitute x=6 into the function above.

1. If the given the function f(x)=\frac{x^{2}}{(3+x)}, you obtain:

f(6)=\frac{6^{2}}{(3+6)}=4

2. If the function is f(x)=x^{(2/3)}+x

Then:

f(6)=6^{(2/3)}+6=9.30

3. If the function is f(x)=\frac{x^{2}}{3}+x

Then:

f(6)=\frac{6^{2}}{3}+6=18

6 0
3 years ago
Read 2 more answers
Jennifer hit a golf ball from the ground and it followed the projectile ℎ(t)= −15t^2+100t, where t is the time in seconds, and ℎ
oksano4ka [1.4K]

Answer:

Step-by-step explanation:

In order to find the max height the ball reached, we have to complete the square on that quadratic. That will also, conveniently so, give us the number of seconds it will take the ball to reach that max height, that answer to part b. Let's begin to complete the square. Normally, you would move the constant over to the other side of the equals sign, but there is no constant here. The next step is to get the leading coefficient to be a 1, and ours right now is a -15. So we have to factor it out. Here's where we start the process of completing the square.

-15(t^2-\frac{20}{3}t)=0 Next step is to take half the linear term, square it, and add it to both sides. Our linear term is 20/3. Half of 20/3 is 20/6, and 20/6 squared is 400/36.

-15(t^2-\frac{20}{3}t+\frac{400}{36})=0+??? Because this is an equation, what we add to the left side also has to be added to the right. BUT we didn't just add in 400/36, because we have that -15 out front as a multiplier that refuses to be ignored. What we actually added in was -15(400/36):

-15(t^2-\frac{20}{3}t+\frac{400}{36})=0-\frac{500}{3}

The reason we do this is to create a perfect square binomial on the left which will serve as the number of seconds, h, in the vertex (h, k), where h is the number of seconds it takes the ball to reach its max height, k. Simplifying both sides then gives us:

-15(t-\frac{20}{6})^2=-\frac{500}{3} Finally, we will move the right side over by the left and set the quadratic back equal to h(t):

h(t)=-15(t^2-\frac{20}{3})^2+\frac{500}{3} and from that you can determine that the vertex is (\frac{20}{3},\frac{500}{3}).

The answer to a. is vound in the second number of our vertex: k, the max height. The max of the golf ball was 500/3 feet or 166 2/3 feet.

Part b is found in the first number of the vertex: h, the number of seconds it took the golf ball to reach that max height. The time it took was 3 1/3 seconds.

Part c. is to state the domain (the time) and the range (the height) of the ball.

Domain is

D: {x | 0 ≤ x ≤ 3 1/3} and

Range is

R: {y | 0 ≤ y ≤ 166 2/3}

8 0
3 years ago
Simplify (2x^2y)^3 (-3xy^2)^2
solniwko [45]
Simplified it's 576x^8y^7
8 0
3 years ago
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