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ikadub [295]
3 years ago
11

Use the rules of multiplication by powers of 10 to calculate 20 times 100.

Mathematics
2 answers:
Kitty [74]3 years ago
8 0
The answer is 2000 because 20 times 100 it equals 2000
Iteru [2.4K]3 years ago
6 0
Its 2000 becasue 200* 10 eqoals 2000
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The answer is A, you would plug in 3 for fx so therefore the answer would be A. Then to make sure plug in the other functions.:)
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Hello pls help meeee<br> )
In-s [12.5K]

Answer:

(4, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = 2x - 7

y = -x + 5

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                                                                                                2x - 7 = -x + 5
  2. [Addition Property of Equality] Isolate <em>x</em> terms:                                            3x - 7 = 5
  3. [Addition Property of Equality] Isolate <em>x</em> term:                                              3x = 12
  4. [Division Property of Equality] Isolate <em>x</em>:                                                       x = 4

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                                                                               y = -x + 5
  2. Substitute in <em>x</em>:                                                                                                y = -4 + 5
  3. Add:                                                                                                                 y = 1
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What is the value of i=
vaieri [72.5K]

\sum\limits_{t=1}^3\left(4\cdot\left(\dfrac{1}{2}\right)^{t-1}\right)=4\cdot\left(\dfrac{1}{2}\right)^{1-1}+4\cdot\left(\dfrac{1}{2}\right)^{2-1}+4\cdot\left(\dfrac{1}{2}\right)^{3-1}\\\\=4\cdot\left(\dfrac{1}{2}\right)^0+4\cdot\left(\dfrac{1}{2}\right)^1+4\cdot\left(\dfrac{1}{2}\right)^2=4\cdot1+4\cdot\dfrac{1}{2}+4\cdot\dfrac{1}{4}\\\\=4+2+1=7\\\\Answer:\ \boxed{D.\ 7}

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DochEvi [55]

Answer:

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Step-by-step explanation:

42/3

14

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