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3 years ago

What are your favorite methods for efficient studying?

2 answers:

wel3 years ago

4 0

The first method for efficient studying I like to use is muting all electronics, this means phones, tablets, computers, and televisions. This is proven to help studying, because you will not be tempted to check every few minutes, and it helps you absorb the course material better without interruption.

Another efficient way for studying is to take notes. Detailed, or blunt, any type of notes you can write, even really quick terminology or vocabulary words, is fantastic. This helps trap the information in your mind.

If you have trouble remembering something, come up with a phrase. For example, if you have to remember, Glucose, Syrup, and Hydrogen, come up with a funny sentence you're sure to remember. "Gretchen sold Helium." This definitely has helped me in the past.

Perhaps have an adult or friend quiz you, or make flash cards to use and study off of, this is simple, and effective!

Another thing you could do is take frequent breaks, and play a video, (despite no electronics,) of the subject you are studying. Close your eyes, and listen quietly to the answers or information!!

I hope this was helpful..

Blizzard [7]3 years ago

3 0

You could make flash cards, make a quizlet, listen to music as you look at past homework/tests on the subject you are studying for, or take breaks periodically as you study.

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Answer:

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2 years ago

Lammps ERROR on proc 0: Out of range atoms - cannot compute PPPM

Alexeev081 [22]

Using the knowledge in computational language in C++ it is possible to write a code that Out of range atoms:

<h3>Writting the code in C++:</h3>

#include <cmath>

#include "pppm_tip4p.h"

#include "atom.h"

#include "domain.h"

#include "force.h"

#include "memory.h"

#include "error.h"

#include "math_const.h"

using namespace LAMMPS_NS;

using namespace MathConst;

#define OFFSET 16384

#ifdef FFT_SINGLE

#define ZEROF 0.0f

#define ONEF 1.0f

#else

#define ZEROF 0.0

#define ONEF 1.0

#endif

void PPPMTIP4P::init()

{

// TIP4P PPPM requires newton on, b/c it computes forces on ghost atoms

if (force->newton == 0)

error->all(FLERR,"Kspace style pppm/tip4p requires newton on");

PPPM::init();

}

void PPPMTIP4P::particle_map()

{

int nx,ny,nz,iH1,iH2;

double *xi,xM[3];

int *type = atom->type;

double **x = atom->x;

int nlocal = atom->nlocal;

if (!std::isfinite(boxlo[0]) || !std::isfinite(boxlo[1]) || !std::isfinite(boxlo[2]))

error->one(FLERR,"Non-numeric box dimensions - simulation unstable");

int flag = 0;

for (int i = 0; i < nlocal; i++) {

if (type[i] == typeO) {

find_M(i,iH1,iH2,xM);

xi = xM;

} else xi = x[i];

nx = static_cast<int> ((xi[0]-boxlo[0])*delxinv+shift) - OFFSET;

ny = static_cast<int> ((xi[1]-boxlo[1])*delyinv+shift) - OFFSET;

nz = static_cast<int> ((xi[2]-boxlo[2])*delzinv+shift) - OFFSET;

part2grid[i][0] = nx;

part2grid[i][1] = ny;

part2grid[i][2] = nz;

if (nx+nlower < nxlo_out || nx+nupper > nxhi_out ||

ny+nlower < nylo_out || ny+nupper > nyhi_out ||

nz+nlower < nzlo_out || nz+nupper > nzhi_out) flag++;

}

int flag_all;

MPI_Allreduce(&flag,&flag_all,1,MPI_INT,MPI_SUM,world);

if (flag_all) error->all(FLERR,"Out of range atoms - cannot compute PPPM");

}

void PPPMTIP4P::make_rho()

{

int i,l,m,n,nx,ny,nz,mx,my,mz,iH1,iH2;

FFT_SCALAR dx,dy,dz,x0,y0,z0;

double *xi,xM[3];

FFT_SCALAR *vec = &density_brick[nzlo_out][nylo_out][nxlo_out];

for (i = 0; i < ngrid; i++) vec[i] = ZEROF;

int *type = atom->type;

double *q = atom->q;

double **x = atom->x;

int nlocal = atom->nlocal;

for (int i = 0; i < nlocal; i++) {

if (type[i] == typeO) {

find_M(i,iH1,iH2,xM);

xi = xM;

} else xi = x[i];

nx = part2grid[i][0];

ny = part2grid[i][1];

nz = part2grid[i][2];

dx = nx+shiftone - (xi[0]-boxlo[0])*delxinv;

dy = ny+shiftone - (xi[1]-boxlo[1])*delyinv;

dz = nz+shiftone - (xi[2]-boxlo[2])*delzinv;

compute_rho1d(dx,dy,dz);

z0 = delvolinv * q[i];

for (n = nlower; n <= nupper; n++) {

mz = n+nz;

y0 = z0*rho1d[2][n];

for (m = nlower; m <= nupper; m++) {

my = m+ny;

x0 = y0*rho1d[1][m];

for (l = nlower; l <= nupper; l++) {

mx = l+nx;

density_brick[mz][my][mx] += x0*rho1d[0][l];

}

}

See more about C++ at brainly.com/question/19705654

#SPJ1

6 0

2 years ago

What is the value of x when -9(x - 5) = x + 22 1/2

tiny-mole [99]

Answer for the question is zero

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3 years ago