Answer:
Range is : { -10, -7, -5, -2 }
Step-by-step explanation:
Given:
The function is given as:
The domain of the function = { -3, 0, 2, 5 }
A function's input is called its domain and a function's output is called its range.
The range depends on the domain values. So, the values of 'y' are the values of range and the values of 'x' are the values of domain.
Here, the domain is given as:
Domain = { -3, 0, 2, 5 }
We need to find the values of 'y' for each value of 'x' taken from the domain set.
Plug in 
. This gives,
Plug in 
. This gives,
Plug in 
. This gives,
Plug in 
. This gives,
Therefore, the set of all values of 'y' is the range.
Range is equal to { -10, -7, -5, -2 }.
Answer:
<em><u>5 is called coefficient</u></em>
<em><u> m is called variable </u></em>
<em><u>3 is called degree....</u></em>
Less. If you multiple 1 2/5 by $2.99 you would get about $4.19. If you multiple 2 3/10 by $2.99 you would get about $6.88. If you add those together, you would get $11.07, which is less than $12.
In order to figure out whether Luis or Isabella skates farther to get to school, we have to create a common denominator between the two fractions that represent the distance that each person walks.
The least common denominator of 3 and 4 is 12. This means that we have to change both fractions into equal fractions with denominators of 12.
To figure this out, we must set up a proportion.
2/3 = x/12
To solve this proportion, we must cross-multiply the fractions. We get:
24 = 3x
If we divide both sides by the coefficient of x which is 3, to get the variable x alone, we get:
x = 8
Therefore, 2/3 = 8/12, so Luis skates 8/12 mile from his home to school.
If we do the same process for the 2/4 mile to get to school for Isabella, we get 6/12, because both fractions are equal to 1/2.
Therefore, we know that Luis skates 8/12 mile to school and Isabella skates 6/12 mile to get to school. Because they have the same denominator, we can just compare the numerators. We know that 8 is greater than 6, thus Luis skates farther to get to school.
What are you trying to do here?
Solve the graph, or make it appear as something else?
First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0
sec (x) (2sec (x) -2) = 0
Then we're going to separate the two to find the zeros of each because anything time 0 is zero.
sec(x) = 0
2sec (x) - 2 = 0
Now, let's simplify the second one as the first one is already.
Add 2 to both sides:
2sec (x) = 2
Divide by 3 on both sides:
sec (x) = 1
I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
