3 years ago

What is the potential difference between the ends of the wire??

1 answer:

7 0

The potential difference between the ends of the wire is (V - IR)

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SVETLANKA909090 [29]

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Explanation:

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$F =\frac{K*m1*m2}{d^2}$

$F=\frac{6.67259 * 10^{-11}*1.56*21.1*10^{-3}}{(5.34*10^{-2})^2}$

$F=7.7*10^{-10}N$

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