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eimsori [14]
3 years ago
12

A cylindrical shell of radius 7.00 cm and length 2.44 m has its charge uniformly distributed on its curved surface. The magnitud

e of the electric field at a point 21.9 cm radially outward from its axis (measured from the midpoint of the shell) is 36.0 kN/C.(a) Use approximate relationships to find thenet charge on the shell.
(b) Use approximate relationships to find theelectric field at a point 4.00 cm from theaxis, measured radiallyoutward from the midpoint of the shell.
Physics
1 answer:
DaniilM [7]3 years ago
5 0

Answer:

(b) Use approximate relationships to find theelectric field at a point 4.00 cm from the axis, measured radiallyoutward from the midpoint of the shell.

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The volume and the mass of substance are 15cm3 and 27 gm respectively find its density​
harina [27]

Answer:

d=1.8\ g/cm^3

Explanation:

Given that,

Mass, m = 27 grams

Volume of the substance, V = 15 cm³

We need to find the density of the substance. We know that, the density of an object is given by mass per unit volume. So,

d=\dfrac{m}{V}\\\\d=\dfrac{27}{15}\\\\d=1.8\ g/cm^3

So, the density of the substance is equal to 1.8\ g/cm^3.

8 0
3 years ago
Please do it to me thank alot
faltersainse [42]

Answer:

See explanations below

Explanation:

For resistors in series, the will be added for those in parallel, we will take the sum of their reciprocal

A) 3 2ohms resistors in series

Equivalent resistance = 2 + 2 + 2

Equivalent resistance = 6ohms

B) 2 4 ohms resisstors in parallal

1/R = 1/4 + 1/4

1/R = 2/4

R = 4/2

R = 4ohms

Equivalent resistance is 2ohms

C) 4 ohms with in series with 8ohms = 4 + 8

Equivalent resistance = 4 + 8

Equivalent resistance = 12ohms

D) 4 ohms and 2 ohms in parallel is expressed as;

1/R = 1/4 + 1/2

1/R = 1+2/4

1/R = 3/4

R = 4/3

4/3 ohms in series with 6ohms

Equivalent resistance = 4/3 + 6

Equivalent resistance =4+18/3

Equivalent resistance = 22/3 ohms

8 0
3 years ago
You move a 25 N object 5 meters. If it takes 8 s how much power did you do?
klasskru [66]

Answer:

15.625 watts

Explanation:

Recall that power is defined as the worked performed per unit of time:

Power = Work / time

The work done is Force * distance, so in our case the work is:

Work = 25 M * 5 m = 125 J

Then the power will be:

Power = 125 J / 8 sec = 15.625 watts

6 0
3 years ago
Which molecules dramatically increases the rate of diffusion of water across cell membranes?
Lorico [155]

Answer:

AQUAPORINS dramatically increases the rate of diffusion of water across cell membranes.

Explanation:

Aquaporins are integral membrane proteins also called water channels that forms pores in the membrane mainly for facilitating diffusion of water molecules in and out of the cell. Aquaporins selectively allow the passage of water molecules while preventing the passage of ions and other solutes through it as they are impermeable to protons, and large solutes. These proteins therefore increases the permeability of the membrane to water molecules and the rate of diffusion of water increases through them. Flow of water molecules in aquaporins follows the direction of osmotic pressure across the membrane. Aquaporins in some organisms have been modified to voltage gated aquaporins which helps them to close the water channels in unfavorable conditions such as drought and flooding. This is to prevent excessive loss of water to the surrounding or intake of water into the cells.

5 0
3 years ago
Which of the following regions of the electromagnetic spectrum has the highest energy
garri49 [273]

Answer:

B. Radiowaves

Explanation:

Radiowaves are on the higher end of the spectrum, then infrared, visible light, and UV light (which is the lowest energy)

6 0
3 years ago
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