Answer:
y=3x.........1
y=x^2-10.......2
substituting value of eq 1 to 2
3x=x^2-10
x^2-10-3x=0
x^2-3x-10=0
x^2-5x+2x-10=0
X(x-5)+2(x-5)=0
(x-5)(X+2)=0
then
X=5 or X=-2
again
y=??
when X=5
y=3×5=15
when X=-2
y=-6
Answer:
<h2>YES. These points are collinear.</h2>
Step-by-step explanation:
If three points are collinear, then the slopes are the same.
The formula of a slope:
For (0, -10) and (-3, -13):
For (-3, -13) and (2, -8):
We can check the last pair (0, -10) and (2, -8):
Convert the percentages in decimals:
90/100 = 0.9, 20/100 = 0.2
Multiply the decimals:
0.9 times 0.2 is 0.18, or 18%
Greg has an 18% chance of being elected both positions.
STAN AND STREAM VICTON ATEEZ AND TXT NOW
<span>Given the diagram, where AB and EF are horizontal lines and CB is a vertical line segment.
Given that FB : FC = 4 : 3,
From the diagram, the coordinate of A is (-10, -8) and the coordinate of C is (-3. -1).
We can also see that the coordinate of B is (-3, -8) (since CB is a vertical line means that B is the same x-value as C and AB is a horizontal line means that B is the same y-value as A)
Recall that the coordinate of a point dividing a line segment in the ratio m:n is given by (x1 + m/(m+n) (x2 - x1), y1 + m/(m+n) (y2 - y1))
Thus, since FB : FC = 4 : 3, this means that point F divides the line segment BC in the ratio 4 : 3.
Thus, the coordinate of F is given by (-3 + 4/(4+3) (-3 - (-3)), -8 + 4/(4+3) (-1 - (-8))) = (-3 + 4/7 (0), -8 + 4/7 (7)) = (-3, -4).
Also, given that FB : FC = 4 : 3, this means that point D divides the line segment AC in the ratio 4 : 3.
Thus, the coordinate of D is given by (-10 + 4/(4+3) (-3 - (-10)), -8 + 4/(4+3) (-1 - (-8))) = (-10 + 4/7 (7), -8 + 4/7 (7)) = (-6, -4).
Therefore, the coordinates of point D is (-6, -4).</span>
