Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
Answer:
from my understanding te correct time will be at 10:15am
Step-by-step explanation:
Answer:
The sum of the age of pupils is 81
Step-by-step explanation:
Let sum of age of 18pupils = x
Average ages = 4.5
Average = total/no. of pupil
4.5 = x/18
x = 81
The conclusion of the remainder theorem about a situation where a function; f(x) is divided by (x+3) and has a remainder of 11 is that; f(-3) = 11.
<h3>What does the remainder theorem conclude given that f(x)/x+3 has a remainder of 11?</h3>
It follows from the task content that f(x)/x+3 has a remainder of 11.
On this note, it follows from the remainder theorem regarding the division of polynomials that; when; x + 3= 0; x = -3 and hence;
f(-3) = 11.
Ultimately, the inference that can be drawn from the remainder theorem statement as in the task content is; f(-3) = 11.
Read more on remainder theorem;
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