Answer:
See below.
Step-by-step explanation:
ABC is an isosceles triangle with BA = BC.
That makes angles A and C congruent.
ABD is an isosceles triangle with AB = AD.
That makes angles ABD and ADB congruent.
Since m<ABD = 72 deg, then m<ADB = 72 deg.
Angles ADB and CDB are a linear pair which makes them supplementary.
m<ADB + m<BDC = 180 deg
72 deg + m<BDC = 180 deg
m<CDB = 108 deg
In triangle ABD, the sum of the measures of the angles is 180 deg.
m<A + m<ADB + m<ABD = 180 deg
m<A + 72 deg + 72 deg = 180 deg
m<A = 36 deg
m<C = 36 deg
In triangle BCD, the sum of the measures of the angles is 180 deg.
m<CBD + m<C + m<BDC = 180 deg
m<CBD + 36 deg + 108 deg = 180 deg
m<CBD = 36 deg
In triangle CBD, angles C and CBD measure 36 deg making them congruent.
Opposite sides DB and DC are congruent making triangle BCD isosceles.
Answer:
2x+4
Step-by-step explanation:
Distribute:
=(2)(x)+(2)(−6)+(2)(8)
=2x+−12+16
Combine Like Terms:
=2x+−12+16
=(2x)+(−12+16)
=2x+4
Answer:
a^14q^10+x^6y^2−b^7+125c
( I hope this was helpful ) >;D
For #2, ∠3 and ∠1 are supplementary. You know that the measure of ∠1 is 162°, so what is ∠3? 180-162=18.
m∠3=18° if ∠1=162°.
Hope this helped!
Answer:
Range is {y | y ≥ –11}
Step-by-step explanation:
This is quadratic equation.
<em>A quadratic equation's range can be found if we find the vertex.</em>
For quadratic equations that have a positive number in front of 
, it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>
The formula for vertex of a parabola is:
Vertex = 
Where,
is the coefficient of 
is the coefficient of 
From our equation given, 
and 
Now, coordinate of vertex is 
coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the value [ 
] into the equation. So we have:
Hence, the range would be all numbers greater than or equal to 
Third answer choice is the right one.
