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earnstyle [38]
4 years ago
8

Student A and Student B are both standing on identical skateboards. Student A is

Physics
1 answer:
andrey2020 [161]4 years ago
7 0

Answer:

0 N

Explanation:

because he is taller and more mass he never go back

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The fundamental frequency of a musical note is 330Hz. Which harmonic is this?
allsm [11]

Answer:

it is a type of even harmonic

6 0
3 years ago
You and your brother argue often about how to safely secure a toddler in a moving car. You insist that special toddler seats are
sergey [27]

Answer:

Force F = 1535.86 N

the force necessary for his wife to hold onto their child during the collision is 1535.86 N

Explanation:

Given;

Mass of toddler m = 13 kg

Velocity v = 37 mi/h = 37 × 0.44704 m/s = 16.54 m/s

Impulse time t = 0.14 seconds

Using the impulse momentum equation,

Impulse = change in momentum

Ft = m(∆v)

Force F = m(∆v)/t

∆v = 16.54 m/s

F = 13×16.54/0.14

Force F = 1535.86 N

5 0
4 years ago
a spacecraft that seems to be motionless in deep space is given some type of quick push. which statement describes what will hap
bogdanovich [222]

An applied force applied causes a body such as the spacecraft to move. The magnitude of the force determines the change in the velocity

What will happen to the spacecraft is given by option C. from among the possible question options.

C. The spacecraft will begin to move and it will continue moving until it is stopped by an equal and opposite force

Reason:

<em>The possible question options obtained from a similar question includes;</em>

<em>A. The spacecraft will move for some time then stop slowly</em>

<em>B. Air resistance will prevent the spacecraft from moving</em>

<em>C. The spacecraft will begin to move and the motion will continue until a force equal and opposite to the applied force stops it</em>

<em>D. The quick push will not cause the spacecraft to move, as a quick push works on Earth only</em>

The state of the space craft = Motionless

Location of the spacecraft = Deep space

Type of force applied = Quick push

The statement that describes what will happen = Required

Solution;

Let <em>F</em>, represent the force applied, and let Δt be the duration of the applied force, we have;

The impulse of the force, F × Δt = m·(v₂ - v₁)

Where;

m = The mass of the spacecraft

v₁ = The initial velocity of the spacecraft = 0

v₂ = Final velocity of the spacecraft

Plugging in v₁ = 0, gives;

F × Δt = m·v₂

The space craft is given a velocity, <em>v₂</em>, and according to Newton's First Law of Motion, it continues moving in a straight line until another force acts on it

Therefore, the correct option is option C. <u>The spacecraft will begin to move and the motion will continue until it is stopped by an equal and opposite force</u>

<u />

Learn more about Newton's First Law of Motion here:

brainly.com/question/20841616

8 0
3 years ago
2. Vehicle-braking distance is the distance your vehicle travels after you see a problem
babunello [35]
The answer is B. False
8 0
3 years ago
Read 2 more answers
How do i find stretch? The problem in questioning has already given me the elastic energy and k-value, but I have no idea how to
finlep [7]

Answer:

Stretch can be obtained using the Elastic potential energy formula.

The expression to find the stretch (x) is x=\sqrt{\frac{2\times EPE}{k}}

Explanation:

Given:

Elastic potential energy (EPE) of the spring mass system and the spring constant (k) are given.

To find: Elongation in the spring (x).

We can find the elongation or stretch of the spring using the formula for Elastic Potential Energy (EPE).

The formula to find EPE is given as:

EPE=\frac{1}{2}kx^2

Rewriting the above expression in terms of 'x', we get:

x=\sqrt{\frac{2\times EPE}{k}}

Example:

If EPE = 100 J and spring constant, k = 2 N/m.

Elongation or stretch is given as:

x=\sqrt{\frac{2\times EPE}{k}}\\\\x=\sqrt{\frac{2\times 100}{2}}\\\\x=\sqrt{100}=10\ m

Therefore, the stretch in the spring is 10 m.

So, stretch in the spring can be calculated using the formula for Elastic Potential Energy.

6 0
3 years ago
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