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3 years ago

I NEED PHYSICS HELP ASAP! DO NOT GUESS! I WILL GIE BRAINLEIST IF RIGHT! THANKS! :D

Physics

2 answers:

ale4655 [162]3 years ago

6 0

<span>The repelling of the support magnet decreases friction. is the answer you're looking for . :)

hope i helped - beanz</span>

suter [353]3 years ago

6 0

Answer:

<h2>The repelling of the support magnet decreases friction.</h2>

Explanation:

The error that Rob is making is to believe that in the Guideway the friction is increased, because it's totally the opposite. In a Electrodynamic Suspension (EDS), the magnets are used to repel the train from the guideway, which decreases friction because levitation is no physical contact. To levitate the train, magnets have to be supercooled and superconducting, once the train levitates, the polarization change constantly to alternate currents and power the system.

The fact that there's no friction and no fuel needed, make this trains a safe transportation source, with no air pollution.

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A 5.67-kg block of wood is attached to a spring with a spring constant of 150 N/m. The block is free to slide on a horizontal fr

nikklg [1K]

Answer:

v=0.94 m/s

Explanation:

Given that

M= 5.67 kg

k= 150 N/m

m=1 kg

μ = 0.45

The maximum acceleration of upper block can be μ g.

a= μ g ( g = 10 m/s²)

The maximum acceleration of system will ω²X.

ω = natural frequency

X=maximum displacement

For top stop slipping

μ g =ω²X

We know for spring mass system natural frequency given as

$\omega=\sqrt{\dfrac{k}{M+m}}$

By putting the values

$\omega=\sqrt{\dfrac{150}{5.67+1}}$

ω = 4.47 rad/s

μ g =ω²X

By putting the values

0.45 x 10 = 4.47² X

X = 0.2 m

From energy conservation

$\dfrac{1}{2}kX^2=\dfrac{1}{2}(m+M)v^2$

$kX^2=(m+M)v^2$

150 x 0.2²=6.67 v²

v=0.94 m/s

This is the maximum speed of system.

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Answer:

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Answer:

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