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solmaris [256]
3 years ago
7

I NEED PHYSICS HELP ASAP! DO NOT GUESS! I WILL GIE BRAINLEIST IF RIGHT! THANKS! :D

Physics
2 answers:
ale4655 [162]3 years ago
6 0
<span>The repelling of the support magnet decreases friction. is the answer you're looking for .  :)

hope i helped - beanz</span>
suter [353]3 years ago
6 0

Answer:

<h2>The repelling of the support magnet decreases friction.</h2>

Explanation:

The error that Rob is making is to believe that in the Guideway the friction is increased, because it's totally the opposite. In a Electrodynamic Suspension (EDS), the magnets are used to repel the train from the guideway, which decreases friction because levitation is no physical contact. To levitate the train, magnets have to be supercooled and superconducting, once the train levitates, the polarization change constantly to alternate currents and power the system.

The fact that there's no friction and no fuel needed, make this trains a safe transportation source, with no air pollution.

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A series RCL circuit contains a 65.2-Ω resistor, a 2.26-μF capacitor, and a 2.08-mH inductor. When the frequency is 2400 Hz, w
raketka [301]

Answer:

The power factor of the circuit is 0.99

Explanation:

Given;

resistance of the resistor, R = 65.2 ohms

capacitance of the capacitor, C = 2.26 μF = 2.26 x 10⁻⁶ F

inductance, L = 2.08 mH = 2.08 x 10⁻³ H

frequency of the AC, f = 2400 Hz

The angular frequency is given by;

ω = 2πf

ω = 2π(2400) = 15081.6 rad/s

The inductive reactance is given by;

XL = ωL

XL = (15081.6 x 2.08 x 10⁻³)

XL = 31.37 ohms

The capacitive reactance is given by;

X_c = \frac{1}{\omega C} \\\\X_c = \frac{1}{(15081.6)(2.26*10^{-6} )}\\\\X_c = 29.34 \ ohms

The phase difference is given by;

tan\phi = \frac{X_l - X_c}{R}\\\\ tan\phi =\frac{31.37-29.34}{65.2} \\\\tan\phi = 0.0311 \\\\\phi  = tan^{-1} (0.0311)\\\\\phi  = 1.78^0

The power factor is given by;

CosФ = Cos(1.78) = 0.99

Therefore, the power factor of the circuit is 0.99

5 0
3 years ago
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