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Nuetrik [128]
3 years ago
11

Arron spends 1/3 of his $890 weekly wage on rent and 1/4 on repaying the loan for his car. How much money does he have left for

other expenses?
Mathematics
2 answers:
Anna007 [38]3 years ago
6 0

Answer:

$370.83.

Step-by-step explanation:

Amount left = 890 - 1/3 * 890 - 1/4*890

= $370.83.

tigry1 [53]3 years ago
4 0

Answer:

(1/4 + 1/3)(890)

(3/12 + 4/12)(890)

(7/12)(890)= 519.17 each. week

519.17 × 4= 2076.68 each month for other expenses

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Find the circumference in inches
Alborosie

Answer:

Step-by-step explanation:

2×radius with pi, 28*pi=28 pi or 87.92

3 0
3 years ago
Read 2 more answers
A factory employs several thousand workers, of whom 35% are Hispanic. If the 17 members of the union executive committee were ch
Elza [17]

Answer:

as p decreases, sigma decreases.

Step-by-step explanation:

Given that 35%are hispanic. For a sample of 17 members

n = 17

p = 0.35

and the number of Hispanics on the committee would have the binomial distribution

a) Mean of X = E(x) = np = 17(0.35)\\= 5.95

b) Std dev X = \sqrt{npq} =\sqrt{5.95(0.65)} \\=1.9665

c) Here n =17 and p =0.1

Mean = 1.7\\\sigma = \sqrt{17(0.1)(0.9)} =1.234

d) When p = 0.01

Mean = 0.17\\\sigma = 0.410

Thus we find that as p decreases, sigma decreases.

8 0
3 years ago
Supply function: 2p-q-63 and the demand function: (p+30)(q+25)=2584. What is the market equilibrium point?
KATRIN_1 [288]
Equilibrium is point where supply = demand

Solve with substitution.

From supply equation ---> q = 2p - 63

Sub into demand equation ---> (p+30)(2p-63+25) = 2584

Solve for p:
2p^2 +22p - 1140 = 2584
p^2 + 11p -1862 = 0
(p+49)(p-38) = 0
p = 38

Sub back into supply equation to find q
q = 2(38) - 63
q = 13

Answer: Equilibrium is 13 units sold at price of $38.
6 0
3 years ago
Can anyone please help me figure this out ​
Fed [463]

Answer:

x=27

Step-by-step explanation:

please give brainly

5 0
3 years ago
Describe the graph of the function. y = |x – 4| – 7
Lemur [1.5K]

Answer:

This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:

(x-4)=0 ===> x=4,

so that now you have to plot 2 functions!

For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:

|x-4| = -(x-4)=4-x

Then:

for x<=4, y = -x+4-7 = -x-3

for x=>4, (x-4) is positive, so no changes:

y= x-4-7 = x-11,

Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11

In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:

x=4 and x= 3 for y=-x-3

And just x=5 for y=x-11

The reason is that the absolute value is continuous, so x=4 works for both:

x=4===> y=-4-3 = -7

x==4 ====> y = 4-11=-7!

abs() usually have a cusp int he point where it is =0

Step-by-step explanation:

5 0
3 years ago
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