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3 years ago

Seven is at most the quotient of a number d and −5 .

Mathematics

1 answer:

defon3 years ago

7 0

Answer: d=-35 Explanation: d/-5=7
D= -5*7
D= -35

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Approximate 0.3632 to 2 decimal places

tamaranim1 [39]

Answer:

0.36

I hope this helps

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3 years ago

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At a bakery, Victor makes 20 cupcakes. He puts them

wariber [46]

It would be B 20/10
Since she puts 10 in each row

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2 years ago

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Carey creates the table below to help him determine 75% of 36. 75% of 36 25% 25% 25% 25% One-fourth One-fourth One-fourth One-fo

alina1380 [7]

Answer:

The correct option is (A).

Step-by-step explanation:

The expression Carey is solving is:

$X=75\%\ \text{of}\ 36$

Simplify the expression as follows:

$X=75\%\ \text{of}\ 36$

$=\frac{75}{100}\times 36\\\\=\frac{3}{4}\times 36\\\\=3\times 9\\\\=27$

So, in Carey's calculation the third step is incorrect.

Instead of 27 the three-fourth must be multiplied by 36 to get the correct answer.

Thus, the correct option is (A).

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3 years ago

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How do you write the number 0.21212121… As a fraction

Dmitry_Shevchenko [17]

21/99 or 7/33 I'm pretty Shure because the numbers repeat, it's probably divided by 9 or some multipule of 9

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6 0

3 years ago

Arrange the expressions in ascending order of their values when x=-2

alex41 [277]

Answer:

The expressions in ascending order would be:

$\frac{3x^2+1}{2(x-1)} < \frac{x^2-1}{1-2x} < \frac{x^2}{1-2x} < \frac{2x^2+x}{2}$

At x = -2

Explanation:

First, we will evaluate the given expressions at x = -2

1- The first expression:

$\frac{x^2}{1-2x}=\frac{(-2)^2}{1-2(-2)}=\frac{4}{5}$

2- The second expression:

$\frac{x^2-1}{1-2x}=\frac{(-2)^2-1}{1-2(-2)}=\frac{3}{5}$

3- The third expression:

$\frac{2x^2+x}{2}=\frac{2(-2)^2+(-2)}{2}=3$

4- The fourth expression:

$\frac{3x^2+1}{2(x-1)}=\frac{3(-2)^2+1}{2(-2-1)}=-\frac{13}{6}$

Then, we will arrange the values in an ascending order:

$-\frac{13}{6} < \frac{3}{5} < \frac{4}{5} < 3$

Finally, we arrange the expressions based on the value arrangement:

$\frac{3x^2+1}{2(x-1)} < \frac{x^2-1}{1-2x} < \frac{x^2}{1-2x} < \frac{2x^2+x}{2}$

Hope this helps :)

6 0

3 years ago