We have been given that Wally wants to determine the height of a statue that casts a 164-inch shadow by comparing it to his own height and shadow length. Wally is 68 inches tall, casts a shadow that is 41 inches in length.

We will use proportions to solve for the height of the statue because proportions state that ratio between two proportional quantities is same.

$\frac{\text{Height of statue}}{\text{Shadow of statue}}=\frac{\text{Height of Wally}}{\text{Shadow of Wally}}$

Upon substituting our given values in above equation, we will get:

$\frac{\text{Height of statue}}{\text{164 cm}}=\frac{\text{68 inch}}{\text{41 inch}}$

$\frac{\text{Height of statue}}{\text{164 cm}}\times \text{164 cm}=\frac{\text{68 inch}}{\text{41 inch}}\times \text{164 cm}$

$\text{Height of statue}=\frac{\text{68 inch}}{1}\times 4$

$\text{Height of statue}=272\text{ inches}$

Therefore, the height of the statue is 272 inches.

5 0

2 years ago

Francesca leaves her home and Drive South 150 km. Then she drives West 70 km. At this point, she drives North 30 km. Finally, sh

Sveta_85 [38]

To find the distance between her home and her latest position:

According to the question, the diagram is,

Consider the right triangle,

AB=120 km

BC=50 km

To find AC:

Using Pythagoras theorem,

$\begin{gathered} AC^2=AB^2+BC^2_{} \\ =120^2+50^2 \\ =14400+2500 \\ =16900 \\ =130\text{ km} \end{gathered}$

Hence, the distance between the new position and her home is 130 km.

8 0

11 months ago

Given that △ABC ≅ △DEF , m∠E=3y+20, m∠B= 10 +5y, and m∠A=5y , answer the following:

Vinvika [58]

Answer:

y=5

m<A= 25

m<E= 35

Step-by-step explanation:

since <E equals <B due to CPCTC the equation:

3y+20=10+5y

is the equation

8 0

9 months ago