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attashe74 [19]
3 years ago
13

two coins and one six sided number cube are tossed together. What is the probability of getting two heads and a four?

Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0

Answer:1/24

Step-by-step explanation:

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Order the data from lest to greatest 35, 24,25,38,31,20,27
kolbaska11 [484]

Answer:

Step-by-step explanation:

20,24,25,27,31,35,38

minimum;20

medium: 27

maximum: 38

lower quartile: 24

upper quartile:35

put numbers in number order

the first number is the minimum, the last number is the maximum. the middle number "split" is the median.

quartiles are the numbers in the middle of the data you just "split"

(so like a quarter)

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Help needed! Plz A graph of a linear inequality in two variables is shown below:
alexandr402 [8]

Answer:

C

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Rewrite using a single positive exponent.<br> 78<br> 73
vivado [14]
Hey! I don’t know if this is what you mean.. but I tried to understand it.

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3 0
2 years ago
.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and
Leni [432]

Answer:

a) Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

b) t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

Step-by-step explanation:

Information given

\bar X=130 represent the sample mean for the amount spent each shopper

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic    

p_v represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

5 0
3 years ago
Whoever answers this correctly gets brainliest
ELEN [110]

Answer: 11. Is A

Step-by-step explanation:

5 0
3 years ago
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