I'm not exactly sure which one but I do know that an acid and a base react in a aqueous solution to form water, so i would probably eliminate the ones that aren't aqueous solutions.
Answer:
0.0300 moles of H₂
Explanation:
The original equation is PV = nRT. We need to change this to show moles (n).
n = 
It's important to convert your values to match the constant (r) in terms of units.
30.0 kPa = 0.296 atm
2500 mL = 2.50 L
27 °C = 300 K
Now, plug those values in to solve:
n = 
- for the sake of keeping the problem clean, I didn't include the units but you should just to make sure everything cancels out :)
Finally, you are left with n = 0.0300 moles of H₂
Answer:
E = 1.5 x 10⁻¹⁷ J
Explanation:
The Rydberg equation for electronic transitions in the hydrogen atom is
1//λ = Rh x ( 1/n₁² - 1/n₂²)
where
Rh : Rydberg´s constant 1.09737 x 10 ⁷ m⁻¹
n₁ : Intial energy Level
n₂ : Final energy Level
But for non-hydrogen one electron ions such as He+ and Li2+ ²⁺ , the equation is similar but multiplied by Z²:
1/ λ = Rh Z² x ( 1/n₁² - 1/n₂²)
I will work this problem by fist calculating 1/λ and then use the equation E= hc/λ where
h : Planck´s constant 6.626 x 10 ⁻³⁴ J s
c : Speed of light 3 x 10 ⁸
1/ λ = 1.09737 x 10 ⁷ m⁻¹ ( 3² ) x ( 1/1² - 1/2² )
1/ λ = 7.4 x 10⁷ m⁻¹
E = 6.626 x 10 ⁻³⁴ J s x 3 x 10^8 m/s x 7.4 x 10⁷ m⁻¹
E = 1.5 x 10⁻¹⁷ J
