Now that we’ve learned how to solve word problems involving the sum of consecutive integers, let’s narrow it down and this time, focus on word problems that only involve finding the sum of consecutive even integers.
But before we start delving into word problems, it’s important that we have a good understanding of what even integers, as well as consecutive even integers, are.
Even Integers
We know that even numbers are integers that can be divided exactly or evenly by 22. Thus, the general form of the even integer nn, is n = 2kn=2k, where kk is also an integer.
In other words, since even numbers are the multiples of 22, we can represent an even integer nn by 2k2k, where kk is also an integer. So if we have the even integers 1010 and 1616,
Let
x---------> the thickness of the frame in feet
At-------> Area of the mirror and the frame in square feet
we know that
------> equation 
--------> equation 
equate equation and equation
therefore
the answer is the option
P + v = 650....p = 650 - v
4p + 9v = 2925
4(650 - v) + 9v = 2925
2600 - 4v + 9v = 2925
-4v + 9v = 2925 - 2600
5v = 325
v = 325/5
v = 65.....video files
p + v = 650
p + 65 = 650
p = 650 - 65
p = 585....photo files
answer : Helena uploaded 9 times as many photo files as video files
65 * 9 = 585
Answer:
To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.
V=43(π)(r3)
In this equation, r is equal to the radius. We can plug the given radius from the question into the equation for r.
V=43(π)(123)
Now we simply solve for V.
V=43(π)(1728)
V=(π)(2304)=2304π
Answer is 2304
