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3 years ago

Write the equation of the line that has a slope of 2 and passing through (3,-4) point

Mathematics

1 answer:

wel3 years ago

4 0

Answer:

$y=2x-10$

Step-by-step explanation:

We know that the line has a slope of 2 and it passes through the point (3, -4).

So, we can use the point-slope form:

$y-y_1=m(x-x_1)$

Where m is the slope and (x₁, y₁) is a point.

So, let’s substitute 2 for m and (3, -4) for (x₁, y₁). This yields:

$y-(-4)=2(x-3)$

Solve for y. Distribute the right:

$y+4=2x-6$

Subtract 4 from both sides. Therefore, our equation is:

$y=2x-10$

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IrinaVladis [17]

Answer:

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Step-by-step explanation:

The students who read less than six magazines would be placed in the intervals: 0-1, 2-3, and 4-5 on the graph. Adding up the total amount in those intervals gives us:

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3 years ago

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Step-by-step explanation:

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3 years ago

You have 15 pennies in your pocket. Of those pennies, 3 are Canadian. Suppose you pick a penny out of your pocket at random. Fin

Lapatulllka [165]

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3 years ago

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It takes 1 3/4 ft of string to complete a violin. If she buys 24 ft of string how many violins can she complete please help

adelina 88 [10]

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3 years ago

Write the point-slope form of an equation of the line through the points (-4, 7) and (5, 3).

cupoosta [38]

Answer:

$y-7=-\frac{\displaystyle 4}{\displaystyle 9}(x+4)$

$y-3=-\frac{\displaystyle 4}{\displaystyle 9}(x-5)$

Step-by-step explanation:

Hi there!

Point-slope form: $y-y_1=m(x-x_1)$ where $m$ is the slope and $(x_1,y_1)$ is a point that falls on the line

1) Determine the slope (m)

$m=\frac{\displaystyle y_2-y_1}{\displaystyle x_2-x_1}$ where two given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (-4, 7) and (5, 3):

$m=\frac{\displaystyle 3-7}{\displaystyle 5-(-4)}\\\\m=\frac{\displaystyle 3-7}{\displaystyle 5+4}\\\\m=\frac{\displaystyle -4}{\displaystyle 9}$

Therefore, the slope of the line is $-\frac{\displaystyle 4}{\displaystyle 9}$ . Plug this into $y-y_1=m(x-x_1)$ as $m$ :

$y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)$

2) Plug a point into $y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)$

$y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)$

Because we're given two points, there are two ways we can write this equation:

$y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)\\\\y-7=-\frac{\displaystyle 4}{\displaystyle 9}(x-(-4))\\\\y-7=-\frac{\displaystyle 4}{\displaystyle 9}(x+4)$

$y-3=-\frac{\displaystyle 4}{\displaystyle 9}(x-5)$

I hope this helps!

4 0

3 years ago