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4 years ago

How are longitudinal and transverse waves alike? How are they different?

2 answers:

8 0

SAME:
- They both transfer energy in waves
- They both have a frequency and period
- Both are mechanical waves and require a medium

DIFFERENT:
- Transverse waves move in a perpendicular direction
- Longitudinal waves move in a parallel direction

nekit [7.7K]4 years ago

4 0

The similarity in the longitudinal and transverse waves is they both transfer energy through the medium and the difference between them is they have different direction of oscillation in the medium.

Further Explanation:

There are two types of waves that propagate through the medium. These two types of the waves are the longitudinal waves and the transverse waves. The both waves are similar to one another in some aspects and are also different to one another.

The similarity between the longitudinal waves and the transverse waves is that they both are the mechanical waves. The both waves carry the energy throughout the medium without the actual movement of the medium particles.

The different between the longitudinal waves and the transverse waves is that the medium particles oscillate in the longitudinal waves in the direction parallel to the propagation of the wave whereas in case of the transverse waves, the medium particles oscillate in the direction perpendicular to the propagation of the wave.

Learn More:

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Choose the 200 kg refrigerator. Set the applied force to 400 n (to the right). Be sure friction is turned off. What is the net force acting on the refrigerator brainly.com/question/4033012

Answer Details:

Grade: High School

Chapter: Waves

Subject: Physics

Keywords: Longitudinal waves, transverse waves, propagation, medium particles, difference, similarities, direction, perpendicular, parallel, transmit energy, medium.

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During a compaction test in the lab a cylindrical mold with a diameter of 4in and a height of 4.58in was filled. The compacted s

Ray Of Light [21]

Answer:

part a : The dry unit weight is 0.0616  $lb/in^3$ 

part b : The void ratio is 0.77

part c : Degree of Saturation is 0.43

part d : Additional water (in lb) needed to achieve 100% saturation in the soil sample is 0.72 lb

Explanation:

Part a

Dry Unit Weight

The dry unit weight is given as

$\gamma_{d}=\frac{\gamma}{1+\frac{w}{100}}$

Here

$\gamma_d$ is the dry unit weight which is to be calculated
γ is the bulk unit weight given as

$\gamma =weight/Volume \\\gamma= 4 lb / \pi r^2 h\\\gamma= 4 lb / \pi (4/2)^2 \times 4.58\\\gamma= 4 lb / 57.55\\\gamma= 0.069 lb/in^3$

w is the moisture content in percentage, given as 12%

Substituting values

$\gamma_{d}=\frac{\gamma}{1+\frac{w}{100}}\\\gamma_{d}=\frac{0.069}{1+\frac{12}{100}} \\\gamma_{d}=\frac{0.069}{1.12}\\\gamma_{d}=0.0616 lb/in^3$

The dry unit weight is 0.0616  $lb/in^3$ 

Part b

Void Ratio

The void ratio is given as

$e=\frac{G_s \gamma_w}{\gamma_d} -1$

Here

e is the void ratio which is to be calculated

$\gamma_d$ is the dry unit weight which is calculated in part a
$\gamma_w$ is the water unit weight which is 62.4 $lb/ft^3$ or 0.04 $lb/in^3$

G is the specific gravity which is given as 2.72

Substituting values

$e=\frac{G_s \gamma_w}{\gamma_d} -1\\e=\frac{2.72 \times 0.04}{0.0616} -1\\e=1.766 -1\\e=0.766$

The void ratio is 0.77

Part c

Degree of Saturation

Degree of Saturation is given as

$S=\frac{G w}{e}$

Here

e is the void ratio which is calculated in part b

G is the specific gravity which is given as 2.72

w is the moisture content in percentage, given as 12% or 0.12 in fraction

Substituting values

$S=\frac{G w}{e}\\S=\frac{2.72 \times .12}{0.766}\\S=0.4261$

Degree of Saturation is 0.43

Part d

Additional Water needed

For this firstly the zero air unit weight with 100% Saturation is calculated and the value is further manipulated accordingly. Zero air unit weight is given as

$\gamma_{zav}=\frac{\gamma_w}{w+\frac{1}{G}}$

Here

$\gamma_{zav}$ is the zero air unit weight which is to be calculated

$\gamma_w$ is the water unit weight which is 62.4 $lb/ft^3$ or 0.04 $lb/in^3$

G is the specific gravity which is given as 2.72

w is the moisture content in percentage, given as 12% or 0.12 in fraction

$\gamma_{zav}=\frac{\gamma_w}{w+\frac{1}{G}}\\\gamma_{zav}=\frac{0.04}{0.12+\frac{1}{2.72}}\\\gamma_{zav}=\frac{0.04}{0.4876}\\\gamma_{zav}=0.08202 lb/in^3\\$