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viva [34]
3 years ago
10

The sticky substances in cigarettes that coat the lining of the lungs are _____.

Physics
2 answers:
Svetach [21]3 years ago
5 0

Answer:

Tar

Explanation: Tar is a big ingredient in cigarettes and can cause the sticky substance

rosijanka [135]3 years ago
5 0

Answer:

Tar

Explanation:

tar is a sticky substance consisting of inorganic and organic compounds.

Tar is very toxic and can cause cancer when deposited on the lungs

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Một đoạn mạch gồm R1=8 ôm;R2=12 ôm.biết R1 nối tiếp với đoạn mạch gồm R2 song song với R3; R3=1/2 R2 cường độ dòng điện chạy qua
LUCKY_DIMON [66]

Answer:

Explanation:

a.

b. R3= 1/2R2=6 ôm

R12= R1+R2=20 ôm

Rtđ=R12.R3/R12+R3= 4,62 ôm

c. U= I.Rtđ = 2.4,62=9,23 V

I1=I2= 9,23/20= 0,4615 A

I3= 2-0,4615=1,5385 A

7 0
2 years ago
A certain carbon monoxide molecule consists of a carbon atom mc = 12 u and an oxygen atom mo = 17 u that are separated by a dist
kvasek [131]

Answer:

a)  x_{cm} = m₂/ (m₁ + m₂)   d , b)   x_{cm} = 52.97 pm

Explanation:

The expression for the center of mass is

                x_{cm} = 1 / M  ∑ x_{i} m_{i}

Where M is the total masses, mI and xi are the mass and position of each element of the system.

Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon

              x_{cm} = 1 / (m₁ + m₂)   (0+ m₂ x₂)

Let's reduce the magnitudes to the SI system

             m₁ = 17 u = 17 1,661 10⁻²⁷ kg = 28,237 10⁻²⁷ kg

             m₂ = 12 u = 12 1,661 10⁻²⁷ kg = 19,932 10⁻²⁷ kg

             d = 128 pm = 128 10⁻¹² m

The equation for the center of mass is

               x_{cm} = m₂/ (m₁ + m₂)   d

b) let's calculate the value

            x_{cm} = 19.932 10⁻²⁷ /(19.932+ 28.237) 10⁻²⁷    128 10-12

            x_{cm} = 52.97 10⁻¹² m

            x_{cm} = 52.97 pm

7 0
3 years ago
How does Ben and Jerry's total displacement compare to their distance traveled?
Sladkaya [172]

Answer:comparing the total displacement and tota distance covered by Ben Jerry.

Explanation:

Total distance travelled by both is;

m+n=z

Total displacement of both is;

x+y=z

Therefore;

comparing equation 1 and 2;

x+y=m+n

5 0
3 years ago
A force is applied to the rim of a disk that can rotate like a merry-go-round, so as to change its angular velocity. Its initial
yawa3891 [41]

Answer:

A = B = C > D

Explanation:

Work done to stop the disc is given as

W = \Delta K

W = \frac{1}{2}I(\omega_f^2 - \omega_i^2)

so we have

(a) –2 rad/s, 5 rad/s;

(b) 2 rad/s, 5 rad/s;

(c) –2 rad/s, –5 rad/s; and

(d) 2 rad/s, –5 rad/s.

So we have

W_a = W_b = W_c = \frac{1}{2}I(5^2 - 2^2)

W_d = \frac{1}{2}I(2^2 - 5^2)

so we have

A = B = C > D

5 0
2 years ago
You have landed on an unknown planet, Newtonia, and want to know what objects will weigh there. You find that when a certain too
steposvetlana [31]

Answer:

w'=5.679\ N on the planet

w=22.43\ N on earth

Explanation:

Given:

  • initial velocity of the tool before pushing, u=0\ m.s^{-1}
  • force applied on the tool, F=12\ N
  • displacement of the tool, s=16.4\ m
  • time taken for the displacement, t=2.5\ s
  • height of releasing  the tool, h=10.3\ m
  • time taken by the tool to fall on the ground, t_v=2.88\ s

<u>Now using the equation of motion:</u>

s=u.t+\frac{1}{2}a.t^2

where:

a = acceleration of the object

16.4=0+0.5\times a\times 2.5^2

a=5.248\ m.s^{-2}

Now the mass of the tool:

m=\frac{F}{a}

m=\frac{12}{5.248}

m=2.2866\ kg

<u>Using the equation of motion when the tool is dropped:</u>

h=u.t_v+\frac{1}{2} \times g.t_v^2

here:

g = acceleration due to gravity on the planet

10.3=0+0.5\times a\times 2.88^2

g=2.4836\ m.s^{-2}

Weight of the tool in the planet:

w'=m.g

w'=2.2866\times 2.4836

w'=5.679\ N

Weight of the tool on the earth:

w=m.g'

w=2.2866\times 9.81

w=22.43\ N

8 0
3 years ago
Read 2 more answers
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